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goblinko [34]
3 years ago
12

PLEASE PLEASE HELP ME WITH THIS QUESTION PLEASE AND SHOW YOUR STEPS PLEASE help me please

Mathematics
1 answer:
jeyben [28]3 years ago
5 0

Answer:

4a)= 2.1m    4b)= 1.9 m    5)= 29.6º

Step-by-step explanation:

4a):

x is the opp

AB is the hyp

BC is the adj

thus,

sin32 = x/4

cross multiply, x= 4*sin32

x= 2.1196.......

x=2.1 m

4b).

x is the hyp

ac is the opp

bc is the adj

thus,

cos65=4.5/x

cross multiply, x= 4.5*cos65

x=1.9017....

x=1.9 m

5).

AB is the opp

bc is the adj

ac is the hyp

thus:

tanC= 2.1/3.7

C= tan^-1 (2.1/3.7)

C= 29.5778.....

C= 29.6º

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Determine which numbers the equations need to be multiplied by to form opposite terms of the y-variable. 3x - 1 4 y = 15 2 3 x -
sesenic [268]

In the elimination method, one variable is eliminated from the system of equations to find the value of the other.

To create the opposite terms of the x-variable-

  • The first equation be multiplied by the number 4.
  • Second equation be multiplied by the number -6.

<h3>What is the elimination method?</h3>

To solve the system of equations and find the value of the variables, the elimination method is used.

In this method, one variable is eliminated from the system of equations to find the value of the other.

Given information-

The system of the equation given in the problem is,

\rm 3x-\dfrac{1}{4}y=15

The second equation given in the problem is;

\rm \dfrac{2}{3}x-\dfrac{1}{6}y=6

To eliminate the x term, make the coefficient of x of both equations equal.

It can be done by multiplying the coefficient of x term of the first equation to the second equation and the coefficient of x term of the second equation to the first equation.

The first equation is multiplied by;

\rm 4\times 3x-4\times \dfrac{1}{4}y=15\times 4\\\\12x-y=50

The second equation is multiplied by;

\rm -6 \times \dfrac{2}{3}x- -6 \times\dfrac{1}{6}y= -6 \times6\\\\-4x-y=-36\\\\4x+y=36

Hence, to create the opposite terms of the x-variable-

The first equation is multiplied by the number 4.

The second equation is multiplied by the number -6.

Learn more about the elimination method here;

brainly.com/question/7013345

6 0
2 years ago
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Find the value of X. Then find the measure of each labeled angle.
wariber [46]
Both angles WILL have the same measure.

So,

3x-10= x+40 (you have to set the equations equal to one another)


Now, add 10 to both sides.

3x=x+50

Subtract x on both sides.

2x=50

Divide both sides by 2.

x=25

Now, plug in x.

(25 +40)= 65

(3(25)-10)= 65

x equals 25 and both angles are equal to 65. Or "B".

I hope this helps!
~cupcake
5 0
3 years ago
What type of conic section is represented by the parametric equations below? X=3cos(t)-1 y=3sin(t)+4
Andrei [34K]

Answer:

Circle

Step-by-step explanation:

Examples of conic sections are the circle, the ellipse, the parabola and the hyperbola. Parametric equations are used to express the x and y variables in terms of a less complicated manner using a third variable (t or θ).

The parametric equation for a circle with an equation (x-h)^2+(y-k)^2=r^2 is given by:

x=rcos(t)+h, y=rsin(t)+k

where r is the radius of the circle and (h, k) is the center of the circle.

A conic section with a parametric equations X=3cos(t)-1, y=3sin(t)+4 is a circle with center at (-1, 4) and radius of 3. The equation of the circle is:

(x + 1)² + (y - 4)² = 3²

3 0
3 years ago
Plz write this on paper help me and send it❤️
vovangra [49]

Answer:

1. 27^{\frac{2}{3} } =9

2. \sqrt{36^{3} } =216

3. (-243)^{\frac{3}{5} } =-27

4. 40^{\frac{2}{3}}=4\sqrt[3]{25} =4325

5. Step 4: (\frac{343}{27}) ^{-1} =\frac{27}{343}

6. D. -72cd^{7}

Step-by-step explanation:

Use the following properties:

a^{\frac{x}{y} } =\sqrt[x]{a^{y} }

\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}

a^{-n} =\frac{1}{a^{n} }

(xy)^{z} =x^{z} y^{z} \\\\

(x^{y}) ^{z} =x^{yz}

x^{y} x^{z} =x^{y+z}

So:

1. 27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9

2. \sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36}  \sqrt{36} =6*6*6=216

3. (-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27

4. 40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325

5. (\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}

6.

(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}

7 0
3 years ago
Taxation without representation is tyranny.
jek_recluse [69]
James Otis made this statement because he <span>believed American colonists should be able to vote in Parliament. The correct option among all the options that are given in the question is the third option or option or the penultimate option. I hope that this answer has come to your help.</span>
3 0
3 years ago
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