Answer:
Huh
Step-by-step explanation:
If the roots to such a polynomial are 2 and

, then we can write it as

courtesy of the fundamental theorem of algebra. Now expanding yields

which would be the correct answer, but clearly this option is not listed. Which is silly, because none of the offered solutions are *the* polynomial of lowest degree and leading coefficient 1.
So this makes me think you're expected to increase the multiplicity of one of the given roots, or you're expected to pull another root out of thin air. Judging by the choices, I think it's the latter, and that you're somehow supposed to know to use

as a root. In this case, that would make our polynomial

so that the answer is (probably) the third choice.
Whoever originally wrote this question should reevaluate their word choice...
A. 30 sixth graders
b. 12 sixth graders
c. If the school has 40 students and the total of students is 70, the number of sixth graders is x
d. 36 students
Answer:
no solution
Step-by-step explanation:
1/2(4x+14)=2(x-7)
Multiply both sides by 2.
4x + 14 = 4(x - 7)
4x + 14 = 4x - 28
Subtract 4x from both sides.
14 = -28
Since 14 = -28 is a false statement, there is no solution for this equation.
Answer: no solution
Answer:
x = 181 and y = 97
Step-by-step explanation:
let called the first number is x
the second number would be called y
We are given that:
x + y = 278 (1)
x = y + 84 (2)
Let change x in (2) into (1):
y + 84 + y = 278
2y + 84 = 278
Subtract 84 from both side, we got:
2y + 84 - 84 = 278 - 84
2y + 0 = 194
Divide both side by 2, we got:
2y / 2 = 194 / 2
y = 97
Because y = 97 and x + y = 278 so x would equal:
x + 97 = 278
Subtract 97 from both side, we got:
x + 97 - 97 = 278 - 97
x + 0 = 181
x = 181 and y = 97
Hope this helped :3