To find the distance between the points given in the figure of the problem above, you must apply the formula for calculate the distace between two points, which is shown below:
d=√[(x2-x1)^2+(y2-y1)^2]
When you substitute the values, you obtain:
d=√[(x2-x1)^2+(y2-y1)^2]
d=√[(-1-2)^2+(-5-5)^2]
d=10.4
The answer is:10.4
The given equation is
where h is the height, in feet, of a ball and t is the time, in seconds.
<u>Part a: The height of the ball when t = 2 seconds:</u>
The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation
, we get;

Simplifying the terms, we get;


Thus, the height of the ball after 2 seconds is 100 feet.
<u>Part b: The height of the ball when t = 4 seconds:</u>
The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation
, we get;

Simplifying the terms, we get;


Thus, the height of the ball after 4 seconds is 68 feet.
Step-by-step explanation:
So, √69 is between 8 and 9 . Since 69 is much closer to 64 than to 81 , the best whole number estimate is 8
23/10 = 2.3 pages per minute.
23. 1
10 = x
23x = 10
X = 10/23 of a minute per page.
Answer:
x = 74°
Step-by-step explanation:
Same side interior angles are supplementary meaning they must add up to 180°.
x = 180° - 106°
x = 74°