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2 years ago

How do I do this? Need help with all, 40 points + brainliest

Mathematics

2 answers:

Elan Coil [88]2 years ago

8 0

I don’t know

Me toooooooooooooooo

oksano4ka [1.4K]2 years ago

5 0

Step-by-step explanation:

I don't know...................GIVE BRAINLIEST PLS

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There are two boxes containing only purple and yellow pens.

UNO [17]

Answer:

I'm not sure what the question is asking here

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2 years ago

Simplify 3(tan^2 theta - sec^2 theta)

Nesterboy [21]

Answer:

sin ^2(x)

Step-by-step explanation:

3 0

2 years ago

The equation of a circle is x2 + (y-10)2=16. The radius of the circle is units. The center of the circle is at .

aliina [53]

Answers:

Center = (0, 10)

Radius = 4

========================================================

Work Shown:

Rewrite the equation into

(x - 0)^2 + (y - 10)^2 = 4^2

Then note how it is in the form

(x - h)^2 + (y - k)^2 = r^2

We see that the center is (h,k) = (0,10) and the radius is r = 4.

8 0

2 years ago

Ella and jade both ran a marathone ella finished 4 hours 6 mins and 13 seconds jade finished in 4 hours and 3 mins and 18 second

spin [16.1K]

Answer:

Jade is faster than Ella by 2 minutes and 55 seconds.

Step-by-step explanation:

We are told that Ella and Jade both ran a marathon. Ella finished marathon in 4 hours 6 mins and 13 seconds. Jade finished marathon in 4 hours and 3 mins and 18 seconds.

We can write 4 hour 6 minutes 13 seconds as 4 hour 5 minutes 73 seconds. 1 minute has been borrowed to the seconds side, and seconds become 13+60 = 73 seconds.

We can see that Ella took more time than Jade. Let us find how much more time Ella took than Jade by subtracting time taken by Jade from time taken by Ella.

$4\text{ hr }5\text{ min }73\text{ sec }-4\text{ hr }3\text{ min }18{ sec }= 2\text{ min }55\text{ sec }$

We can see that Jade took 2 minute and 55 seconds less than Ella , therefore, Jade was faster than Ella by 2 minutes 55 seconds.

4 0

2 years ago

A fish was swimming LaTeX: 2\frac{1}{2}2 1 2 feet below the water's surface at 1:00 p.M. Three hours later, the fish was at a de

marin [14]

Answer:

$\frac{23}{4}$ feet

Step-by-step explanation:

The depth of the fish to the surface of water at 1:00 pm = 2 $\frac{1}{2}$ feet

= $\frac{5}{2}$ feet

The depth of the fish to its initial position at 4:00 pm = 3 $\frac{1}{4}$ feet

= $\frac{13}{4}$ feet

The position of the fish with respect to the water's surface at 4:00 pm = the depth of the fish to the surface of water at 1:00 pm + the depth of the fish to its initial position at 4:00 pm

= $\frac{5}{2}$ + $\frac{13}{4}$

= $\frac{10 + 13}{4}$

= $\frac{23}{4}$

The position of the fish with respect to the water's surface at 4:00 pm is $\frac{23}{4}$ feet.

8 0

2 years ago