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KatRina [158]
3 years ago
9

Help im markin brainlest for who is right

Mathematics
1 answer:
nirvana33 [79]3 years ago
5 0
What’s the question??
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Simplify the following: 6i^3 +4j^2 -6i<br> Please show work
Vadim26 [7]

Answer:

Concept: Vectors

  1. I think the confusion here might be the usage of i and j
  2. Just to let you know, i=x and j=y
  3. So let's use that fact to conceptualize this
  4. 6x^3+4y^2-6x
  5. We can simplify by applying a common factor
  6. 2(x^3+2y^2-3x)
  7. Thats the most we can simplify this
6 0
2 years ago
Can someone help me with 3,4,5 please?
anzhelika [568]

Answer:

the approximate range of change is 150 for 3

the approximate range of change is 1600 for 4

between 1970 and 1975

please give me brainlest

7 0
3 years ago
among 210 student 85 price in English 125 price in Nepali and 25 failed in both subject find the number of students who passed i
notka56 [123]

Answer:

210=85+125-x+25

x= 235-210

x=25 failled in both

Step-by-step explanation:

5 0
2 years ago
HELP ME PLEASE I REALLY NEED THE HELP​
dedylja [7]

Answer:

Answer = 126 square inches

Step-by-step explanation:

Square area formula is Area = s^2    (replace the s with the side length)

Square area -->  Area = 4^2       Area = 16in

Parallelogram area formula is Area = h * b (replace h with height length and replace b with base length)

Parallelogram area --> Area = 3.5 * 10     Area = 35

Rectangle area formula is Area = w * h    (replace width and height)

Rectangle area --> Area = 12.5 * 6    Area = 75

Then add them all up  75 + 35 + 16 = 126 square inches

3 0
3 years ago
Solve 3cot (2x) =- Route3 for<br> x, 0 = x &lt; 360
ivolga24 [154]

Answer:

x=60,150,240,330

Step-by-step explanation:

3 \cot(2x)  =  -  \sqrt{3}

\cot(2x)  =  \frac{  - \sqrt{3} }{3}

Take the arc cot of both sides

\cot {}^{ - 1} ( \cot(2x) )  =  \cot {}^{ - 1} (  \frac{ -  \sqrt{3} }{3}  )

2x = 120

Remember cotangent has a period of 180 degrees

2x = 120 + 90(n)

where n is 0, 1,2,3,4,5.....

Isolate x.

x = 60 + 90(n)

where n is 0, 1,2,3,4,5,6.

Keep plugging in integers as long they are in the interval [0,360].

We get

60,150,240,330.

6 0
2 years ago
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