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motikmotik
3 years ago
15

Barney and Betty break into a parking meter with $3.90 in dimes and quarters in it (legal disclaimer: don't do this) and agree t

hat Barney will get all the dimes, and Betty will get all the quarters. (Barley isn't terribly bright) Barney ends up with four more coins than Betty. How much money did each get(
Mathematics
1 answer:
Crank3 years ago
7 0

Answer:

Barney got 14 dimes and Betty got 10 quarters.

Step-by-step explanation:

Since there are only dimes and quarters in the parking meter, the total money must be equal to:

0.1*dimes + 0.25*quarters = 3.9

Since Barney got all the dimes and he has four more coins than Betty, then the number of dimes is:

dimes = quarters + 4

Applying the second expression on the first, we have:

0.1*(quarters + 4) + 0.25*quarters = 3.9\\0.1*quarters + 0.4 + 0.25*quarters = 3.9\\0.35*quarters = 3.9 - 0.4\\0.35*quarters = 3.5\\quarters = \frac{3.5}{0.35} = 10

dimes = quarters + 4 = 10 + 4 = 14

Barney got 14 dimes and Betty got 10 quarters.

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andrezito [222]

Given:

The two way table.

To find:

The conditional probability of P(Drive to school | Senior).

Solution:

The conditional probability is defined as:

P(A|B)=\dfrac{P(A\cap B)}{P(B)}

Using this formula, we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{P(\text{Drive to school and senior})}{P(\text{Senior})}                      ...(i)

From the given two way table, we get

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Now,

P(\text{Drive to school and senior})=\dfrac{25}{100}

P(\text{Senior})=\dfrac{35}{100}

Substituting these values in (i), we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{\dfrac{25}{100}}{\dfrac{35}{100}}

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Therefore, the required conditional probability is 0.71.

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3 years ago
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