Answer:
7.83 repeating
Step-by-step explanation:
Cal’s
Answer:
18598
Step-by-step explanation:
just add
Answer:
<h3>
f(x) = - ⁴/₉(x - 3)² + 6</h3>
Step-by-step explanation:
The vertex form of the equation of the parabola with vertex (h, k) is:
f(x) = a(x - h)² + k
So for vertex (3, 6) it will be:
f(x) = a(x - 3)² + 6
<u>y intercept: 2</u> means f(0) = 2
f(0) = a(0 - 3)² + 6
2 = a(-3)² + 6
2 -6 = 9a + 6 -6
-4 = 9a
a = ⁻⁴/₉
Therefore:
The vertex form of quardatic function with vertex: (3,6) and y intercept: 2 is
<u>f(x) = - ⁴/₉(x - 3)² + 6</u>
Mind sharing the information needed to answer the question? Thanks!
This is the eqn of a str line. <span>y+4=12/7(x-1) would be clearer if written as
</span><span>y+4=(12/7)(x-1). y+4 = (12/7)x - 12/7.
Multiply all terms by 7 to remove the fractions: 7(y+4) = 12x - 12.
Complete the multiplication: 7y + 28 = 12x - 12.
Arrange the x and y terms on the left side and the constants on the right:
-12x + 7y = -40. This is standard form. Some people might disagree and say that -12x + 7y + 40 is standard form. They are equivalent.
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