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tatyana61 [14]
3 years ago
9

Use the figure below to answer the following questions.

Mathematics
1 answer:
yan [13]3 years ago
5 0

Answer:

40

Step-by-step explanation:

why ? because the total angle measure in triangle is 180degree so we have a right angled triangle so 90+50 = 140

180-140 = 40

hope it's correct

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Two angles are said to be congruent if
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Answer:

Two line segments are congruent if they have the same length. Two angles are congruent if they have the same measure.

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3 years ago
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The sum of the angle measures of a polygon with s sides is 2520. Find s.
Anna007 [38]
(n-2)*180=Sum of angle  
(n-2)*180=2520
(n-2)=2520/180

n=14+2

n=16

5 0
4 years ago
What is the rate of change (as a %) if the number of employees in a company decreases from 136 to 84?
Law Incorporation [45]

Answer:

38.2%

Step-by-step explanation:

Given data

Initial number= 136

FInal number= 84

%dcrease= initial-final/initial*100

%dcrease= 136-84/136*100

%dcrease= 52/136*100

%dcrease=0.382*100

%dcrease=38.2%

Hence the decrease is 38.2%

5 0
3 years ago
Assume that male and female births are equally likely and that the birth of any child does not affect the probability of the gen
Aleksandr-060686 [28]

Let X be the number of boys in n selected births. Let p be the probability of getting baby boy on selected birth.

Here n=10. Also the male and female births are equally likely it means chance of baby boy or girl is 1/2

P(Boy) = P(girl) =0.5

p =0.5

From given information we have n =10 fixed number of trials, p is probability of success which is constant for each trial . And each trial is independent of each other.

So X follows Binomial distribution with n=10 and p=0.5

The probability function of Binomial distribution for k number of success, x=k is given as

P(X=k) = (10Ck) 0.5^{k} (1-0.5)^{10-k}

We have to find probability of getting 8 boys in n=10 births

P(X=8) = (10C8) 0.5^{8} (1-0.5)^{10-8}

= 45 * 0.0039 * 0.25

P(X = 8) = 0.0438

The probability of getting exactly 8 boys in selected 10 births is 0.044

8 0
4 years ago
Which expression is a difference of cubes? 9w^33-y^12 18p^15-q^21 36a^22-b^16 64c^15- a^26
LiRa [457]

we know that

A polynomial in the form a^{3}-b^{3} is called adifference of cubes. Both terms must be a perfect cubes

Let's verify each case to determine the solution to the problem

<u>case A)</u> 9w^{33} -y^{12}

we know that

9=3^{2} ------> <u>the term is not a perfect cube</u>

w^{33}=(w^{11})^{3} ------> the term is a perfect cube

y^{12}=(y^{4})^{3} ------> the term is a perfect cube

therefore

The expression 9w^{33} -y^{12} is not a difference of cubes because the term 9 is not a perfect cube

<u>case B)</u> 18p^{15} -q^{21}  

we know that

18=2*3^{2} ------> <u>the term is not a perfect cube</u>

p^{15}=(p^{5})^{3} ------> the term is a perfect cube

q^{21}=(q^{7})^{3} ------> the term is a perfect cube

therefore

The expression 18p^{15} -q^{21} is not a difference of cubes because the term 18 is not a perfect cube

<u>case C)</u> 36a^{22} -b^{16}

we know that

36=2^{2}*3^{2} ------> <u>the term is not a perfect cube</u>

a^{22} ------>  <u>the term is not a perfect cube</u>

b^{16} ------> <u>the term is not a perfect cube</u>

therefore

The expression 36a^{22} -b^{16} is not a difference of cubes because all terms are not perfect cubes

<u>case D)</u> 64c^{15} -a^{26}

we know that

64=2^{6}=(2^{2})^{3} ------>  the term is a perfect cube

c^{15}=(c^{5})^{3} ------>   the term is a perfect cube

a^{26} ------> <u>the term is not a perfect cube</u>

therefore

The expression 64c^{15} -a^{26} is not a difference of cubes because the term a^{26} is not a perfect cube

I'm adding a new case so I can better explain the problem

<u>case E)</u> 64c^{15} -d^{27}

we know that

64=2^{6}=(2^{2})^{3} ------>  the term is a perfect cube

c^{15}=(c^{5})^{3} ------>   the term is a perfect cube

d^{27}=(d^{9})^{3} ------>  the term is a perfect cube

Substitute

64c^{15} -d^{27}=((2^{2})(c^{5}))^{3}-(d^{9})^{3}

therefore

The expression 64c^{15} -d^{27} is a difference of cubes because all terms are perfect cubes



5 0
3 years ago
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