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luda_lava [24]
3 years ago
10

The equation of line v is y=9x+1. Line w is perpendicular to line v and passes through (3, – 2). What is the equation of line w?

Mathematics
1 answer:
Anna11 [10]3 years ago
7 0

Answer:

Step-by-step explanation:

Remember the general form of a linear equartion: y=mx + b, where m is the slope and b is the y-intercept (the value of y when x = 0).

The equation of line v (y=9x+1) has a slope of 9. A perpendicular line with have a slope equal to the negative inverse of the reference line. So the line we want will have a slope of -(1/9). That gives us y = -(1/9)x + b. Any vale of b will produce a line that is perpendicular. But we want a line that goes through point (3,-2). All we need to do is find a value for b that will make that wish come true.

Use the point (3,-2) in y = -(1/9)x + b and solve for b:

y = -(1/9)x + b

-2 = -(1/9)*(3) + b

-2 = -(1/3) + b

b = - 1 2/3, or -(5/3)

The equation is y = -(1/9)x + - (5/3)

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Which  quadrant will the complex number (10 - 13i) be  found.

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Therefore, the complex number is in 4th quadrant.

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Answer:

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Step-by-step explanation:

From the above question:

Stan ran 4 and StartFraction 7 Over 10 EndFraction miles

The number of miles stan ran =

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We are also told that this number of miles was 1 and StartFraction 3 Over 10 EndFraction fewer miles than Matt ran.

Let the number of miles Matt ran = m

Hence,

4 7/10 miles = m - 1 3/10

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m = (4 + 1) + ( 7/10 + 3/10)

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Step-by-step explanation:

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In this case, Initial = 300, r = 0.06 and t=10 so the total amount in the account after 10 years is:

\begin{gathered} \text{Amount}=300\cdot(1+0.06)^{10} \\ \text{Amount}=300\cdot1.06^{10} \\ \text{Amount}=300\cdot1.79085 \\ \text{Amount}=537.255 \end{gathered}

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