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docker41 [41]
3 years ago
10

Joe brought 17 packs of cola to a party, and each pack had 8 cans. Teresa brought 6 cans of juice. How many cans did they bring

in all?
Mathematics
2 answers:
KATRIN_1 [288]3 years ago
6 0

Answer:

Hello!!

If Joe brought 17 packs of cola to a party, and each pack had 8 cans. Teresa brought 6 cans of juice. They brought 142 cans in all.

Step-by-step explanation:

17×8=136

136+6=142

Hope this helps!!

o-na [289]3 years ago
6 0

Answer:  31

Step-by-step explanation: Addition, 17 + 8 = 25 + 6 = 31

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a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.​
Inessa05 [86]

Answer:

Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.

** Due east has an angle measure of 0 degrees

Now let's begin.

We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

A_x=50cos(89.75) so

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B_x=200cos(0) so

B_x=200 and we need to add those results together. Due to the rules for adding significant digits properly, the answer is

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Now for the y components:

A_y=50sin(89.75) so

A_y=50 (which I'm counting as 2 sig fig's)

B_y=200sin(0) so

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C_y=50

Now for the resultant magnitude:

C_{mag}=\sqrt{(200)^2+(50)^2}  and that gives us a final magnitude of

C_{mag}=206 m

Now for the angle:

Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so

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Answer:

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