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aleksandrvk [35]
4 years ago
8

Help me please,Thanks;) ONLY IF YOU KNOW THE CORRECT ANSWERS

Mathematics
2 answers:
ser-zykov [4K]4 years ago
6 0
Number twenty-eight is d. Number 29 is c.
Aneli [31]4 years ago
5 0
28) x+x+x+5+5
because there are 3 x's that makes 3x
and then add the 5's to get 10
D) 3x10
29) like terms have the same variable because none of the terms have the same variable there are no like terms
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There are 5 sales person and 22 clients if of each client only deals with one sales person and the client are divided as equally
Mariana [72]

Answer:

2 sales person

Step-by-step explanation:

If there are 5 sales person and 22 clients

Therefore:

1 sales Person will be responsible for \frac{22}{5}=4\frac{2}{5} Client.

Therefore: 2 sales person will be responsible for 5 clients since there must be equal distribution.

4 0
4 years ago
What is equivalent to n – 4.6n – 3.3n + 2.8n
Ahat [919]

Answer:

4.1n

Step-by-step explanation:

Let's simplify step-by-step.

n−4.6n−3.3n+2.8n

=n+−4.6n+−3.3n+2.8n

Combine Like Terms:

=n+−4.6n+−3.3n+2.8n

=(n+−4.6n+−3.3n+2.8n)

=−4.1n

7 0
3 years ago
Natalie sawed 5 boards of equal length to make a stool. Each was 9/10 of a meter long. What is the total length of the boards sh
STALIN [3.7K]
total length of the boards = 4 1/2 meters

Given:
number of boards = 5
length of each board = 9/10 meters

5 * 9/10 = (5*9)/10 = 45/10
Simplify fraction:
45/10 = 4 5/10 or 4 1/2 meters.
5 0
4 years ago
A football field measures 300 feet in length. It can also be expressed as approximately 5 7x 10miles. If the
kogti [31]

Answer:

The question is incomplete or there are details missing.

Step-by-step explanation:

From similar parameters, if by what they mean is that the football field measures 300feet in length, which is the dimension in length, this can also be in terms of metre.

The conversion factor between ft and metre is 1ft = 0.3048m

As such, we can only have variations or the length of the field measured may have ranges of measurement,  but as it is the length of the field can not be expressed in terms of miles, the most reasonable vale of n we can get will be the least measurement in metres.

3 0
3 years ago
Find the area of a 2-inch-wide decorative border around a rectangular canvas painting, where L is the length and W is the width
lions [1.4K]

Answer:

  4L +4W +16 square inches

Step-by-step explanation:

The area of the border is the equivalent of that of a rectangle with a width equal to the width of the border, and a length equal to the length of the midline of the border. That length is the perimeter of the rectangle that is L+2 units long and W+2 units wide.

  border midline length = 2((L+2) +(W+2)) = 2L +2W +8

Then the border area is ...

  border area = (border width)(border length) = (2)(2L +2W +8)

  border area = 4L +4W +16 . . . square inches

_____

You can also figure this as the difference between the area of the rectangle with the border and the area of the rectangle inside the border:

  border area = total area - canvas area

  = (L+4)(W+4) -LW = LW +4L +4W +16 -LW

  = 4L +4W +16 . . . . square inches

4 0
3 years ago
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