Step-by-step explanation:
Answer:
in this method a variable is expressed in terms of another variable from one equation and it is substituted in remaining equation.
Step-by-step explanation:
solve:x+2y=9 and 3x-y=13.
x+ 2y=9…be the first equation
3x-y=13…be the second equation
from first equation
x=9-2y…be the third equation substituting value of x from third equation in second equation, we get
3(9-2y)-y=13
or, 27-6y-y=13
or, y=2
now,
substituting value of y in third equation, we get,
x=9-2×2
=9-4
=5
the required value of x and y are 5&2
The x-intercept is 12 and the y-intercept is -2
The first thing you do is substitute 9 for y in the function, which is,
9 - 4 = 5/6 (x - 2)
Then, you subtract on the left side
5 = 5/6 (x - 2)
Then, you multiply by 6 on both sides
30 = 5 (x - 2)
Then, divide both sides by 5
6 = x - 2
Then, at 2 on both sides to isolate x
& your final answer is
x = 8 (this would be the missing value)
Answer:
44+
Step-by-step explanation:
just got it correct
