Find two consecutive integers whose sum is 45.

Mathematics

2 answers:

postnew [5]3 years ago

6 0

My answer is 22 and 23 and their both integers

babymother [125]3 years ago

3 0

Answer:

22 followed by 23

Step-by-step explanation:

These are well known integers that are common with the following number 45. hope this help a

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H(x) = x3 + 7<br> Determine whether the function is one-to-one.

zubka84 [21]

Answer:

we conclude that the function is one-to-one.

Step-by-step explanation:

A function will a one-to-one function if it

passes the vertical line test to make sure it is indeed a function, and

also a horizontal line test to make sure it is it one-to-one.

In other words,

The function will be one-to-one if it passes the vertical line test, and also if the horizontal line only cuts the graph of the function in one place.

The reason is that there must be only one x-value for each y-value.

Given the function

$h\left(x\right)\:=\:x^3\:+\:7$

Have a look at the attached graph.

The red portion represents the graph of the function $h\left(x\right)\:=\:x^3\:+\:7$ .

The green portion represents the graph of x=2 which is basically a vertical line test. Vertical line indicates that it cuts the cuts the graph of the function in one place. So it is clear that $h\left(x\right)\:=\:x^3\:+\:7$ is indeed a function.

The blue line represents the graph of y=9, which is basically a horizontal line test. Horizontal line indicates that it cuts the cuts the graph of the function in one place. So it is clear that $h\left(x\right)\:=\:x^3\:+\:7$ is a one-to-one function, as there is only one x-value for each y-value.

Therefore, we conclude that the function is one-to-one.

6 0

3 years ago

Ashley is packing her bags for her vacation. She has 8 unique Fabergé eggs, but only 5 fit in her bag. How many different groups

irakobra [83]

Answer:

56 groups of 5 Fabergé eggs can be taken.

Step-by-step explanation:

It is given that Ashley is packing her bags for her vacation. She has 8 unique Fabergé eggs, but only 5 fit in her bag. In order to find how many different groups of 5 Faberge' eggs can she take, we apply the combination formula:

$8C_{5}=\frac{8!}{5!(8-5)!}$