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2 years ago

Does anyone know how to solve these?

Mathematics

1 answer:

bixtya [17]2 years ago

8 0

<AEB and <DEC are equal so:
5x-10=3x+40
5x-3x=40+10
2x=50
x=25
<AEB= 5x-10
<AEB= 5*25-10
<AEB=115

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Using diagonals from a common vertex, how many triangles could be formed from a hexagon?

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The Henley's took out a loan for $195,000 to purchase a home. At a 4.3% interest rate

ella [17]

Interest paid after 30 years is $494,546.99.

Solution:

Principal (P) = $195,000

Interest rate (r) = 4.3%

Time (t) = 30 years

n = number of times interest calculated per year

n = 1

Compound interest formula:

$$A=P\left(1+\frac{r}{n}\right)^{n t}$

where A is the final amount

$$A=195000\left(1+\frac{4.3\%}{1}\right)^{1\times 30}$

$$A=195000\left(1+\frac{4.3}{100}\right)^{30}$

$$A=195000\left(\frac{100+4.3}{100}\right)^{30}$

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A = 689546.99

Interest = Amount - Principal

= 689546.99 - 195000

= 494546.99

Interest paid after 30 years is $494,546.99.

6 0

3 years ago

Miss Krin has $300 deducted from her checking account every month for her car payment she also has $150 deducted every month for

n200080 [17]

Did the question mention what her current checking account balance was ?

5 0

2 years ago

Read 2 more answers

An object is launched from a launching pad 208 ft. above the ground at a velocity of 192ft/sec. what is the maximum height reach

Alexeev081 [22]

Answer:

h(x) = -16x² + 192x + 208

784ft

6 sec

13 sec

Step-by-step explanation:

h(x) = -16x² +vx + h $_{o}$

here v represent velocity

$h_{o}$ represent initial height of launch

h(x) = -16x² + 192x + 208

here a = -16

b = 192

c = 208

x = -b/2a

= -192/2(-16)

= 6

plug this value in the equation

h(x) = -16(6)² + 192(6) + 208

= 784ft

Plug h(x)=0 in the equation

0 = -16x² + 192x + 208

divide equation by -16

x² - 12x - 13 = 0

Factors

1x * -13x = -13

1x - 13x = -12

Factorised form

x² - 12x - 13 = 0

x² + x - 13x - 13 = 0

x(x+1) -13(x+1) = 0

(x+1)(x-13) = 0

x = -1

x = 13

Since time can not be negative so we will reject x = -1

3 0

3 years ago

Evaluate the expression 2b^3+5 (BTW I did the first part it's 3 but I need the second part)

andrey2020 [161]

To find the exact answer based on the last step, " $2(3)^3+5$ ", you must use PEMDAS (attached image below)

$2(3)^3+5=2*27+5=54+5=59$

Thus the answer is <u>59</u>.

Hope that helps!

4 0

2 years ago