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Nesterboy [21]
3 years ago
9

Does anyone know how to solve these?

Mathematics
1 answer:
bixtya [17]3 years ago
8 0
<AEB and <DEC are equal so:
5x-10=3x+40
5x-3x=40+10
2x=50
x=25
<AEB= 5x-10
<AEB= 5*25-10
<AEB=115
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Benny thinks of a number, subtracts 18 from it, and divides the difference by 3, the result is (-4). What is the number?
White raven [17]

Answer:

n=6

Step-by-step explanation:

(n-18)/3 = -4

multiply by 3

n-18 = -12

add 18

n = 6

7 0
3 years ago
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The area of a trapezoid is 864cm². It has a height of 24 cm, and the length of one of its bases is 30 cm. What is the length of
Amiraneli [1.4K]

The area <em>A</em> of a trapezoid with height <em>h</em> and bases <em>b</em>₁ and <em>b</em>₂ is equal to the average of the bases times the height:

<em>A</em> = (<em>b</em>₁ + <em>b</em>₂) <em>h</em> / 2

We're given <em>A</em> = 864, <em>h</em> = 24, and one of the bases has length 30, so

864 = (<em>b</em>₁ + 30) 24 / 2

864 = (<em>b</em>₁ + 30) 12

864 = (<em>b</em>₁ + 30) 12

72 = <em>b</em>₁ + 30

<em>b</em>₁ = 42

5 0
3 years ago
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Ilya [14]

Answer:

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Step-by-step explanation:

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Hope that helped!!! k

8 0
3 years ago
What is the horizontal asympote of this graph?
Anna35 [415]

Using it's concept, it is found that the graph has no horizontal asymptote.

<h3>What are the horizontal asymptotes of a function f(x)?</h3>

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, we have that:

  • The function is undefined for x < 0, hence \lim_{x \rightarrow -\infty} f(x) is undefined.
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Thus, the graph has no horizontal asymptote.

More can be learned about horizontal asymptotes at brainly.com/question/16948935

#SPJ1

4 0
2 years ago
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sattari [20]

Answer:

a = 49°

Step-by-step explanation:

OB = OC ( both radii of the circle ), thus

Δ BOC is isosceles and the base angles are congruent, that is

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The angle on the circumference BAC is half the angle at the centre for angles subtended on the same arc , thus

a = 0.5 × 98° = 49°

5 0
3 years ago
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