All categories

3 years ago

Simplify the linear expression.

Mathematics

1 answer:

Nataliya [291]3 years ago

6 0

Answer:

-7/8a-1/6

Step-by-step explanation:

You might be interested in

You have eight coins in your pocket that equal $1.02. What are the eight coins?

Dimas [21]

2 pennies
3 quarters
2 dimes
1 nickel

4 0

3 years ago

A manager at a pizza shop wants to start visually checking finished pizzas, but she doesn't have time to check every pizza. She

SashulF [63]

Answer:

Systematic sampling

Step-by-step explanation:

Systematic sampling is a form of random sampling that involves sampling based on numbering the members of the population and selecting the sample at a given specified interval.

However, when the systematic sampling technique is used, it is necessary to ensure that the numbering of the population does not result in an ordering of the population such that the selected sample will consist more of a particular group of the population.

8 0

3 years ago

Which of the following numbers has the smallest value? 19.45 19.445 19.5 19.454

den301095 [7]

Answer:

19.445

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What's the axis of symmetry of y = 3x2 - 6x + 4

Alex17521 [72]

Answer:6x+6... not sure

Step-by-step explanation:

Sry if I’m wrong

3 0

3 years ago

Read 2 more answers

The time between arrivals of taxis at a busy intersection is exponentially distributed with a mean of 10 minutes. (a) What is th

Sindrei [870]

Answer:

a) 0.0025

b) 0.9975

c) 23.03 minutes

d) 23.03 minutes

Step-by-step explanation:

Let X be the random variable that measures the time waited for a taxi.

If X is exponentially distributed with a mean of 10 minutes,then the probability that you have to wait more than t minutes is

$\large P(X>t) = e^{-t/10}$

1 hour = 60 minutes, so the probability that you wait longer than one hour is

$\large P(X>60)=e^{-6}=0.0025$

Due to the “memorylessness” of the exponential distribution, the probability that you have to wait 10 or less minutes after you have already waited for one hour, is the same as the probability that you have to wait 10 or less minutes

$\large P(X\leq 10)=1-e^{-6}=0.9975$

We want x so that

P(X>x)=0.1

$\large e^{-x/10}=0.1\rightarrow -x/10=ln(0.1)\rightarrow x=-10ln(0.1)=23.03\;minutes$

We want P(X<x)=0.9

$\large 1-e^{-x/10}=0.9\rightarrow e^{-x/10}=0.1\rightarrow x=-10ln(0.1)=23.03\;minutes$

4 0

3 years ago