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AURORKA [14]
2 years ago
7

Equation of the parabola in vertex form that passes through (4,-7) and has a vertex of (1,-6)

Mathematics
1 answer:
Alina [70]2 years ago
7 0

y = -\frac{1}{9}(x - 1)^2 - 6

Step-by-step explanation:

The vertex form of the equation for a parabola is given by

y = a(x - h)^2 + k

where (h, k) are the coordinates of the parabola's vertex. Since the vertex is at (1, -6), we can write the equation as

y = a(x - 1)^2 - 6

Also, since the parabola passes through (4, -7), we can use this to find the value for a:

-7 = a(4 - 1)^2 - 6 \Rightarrow -7 = 9a - 6

or

a = -\frac{1}{9}

Therefore, the equation of the parabola is

y = -\frac{1}{9}(x - 1)^2 - 6

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Alexus [3.1K]

rewrite -1 1/3 as a decimal: -1.5


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Subtract -2.1 From both sides:

X = -1.5 - -2.1 = -1.5 + 2.1

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Allen's work is not written properly so I have rearranged it as shown below:


Original problem) –8.3 + 9.2 – 4.4 + 3.7.

Step 1) −8.3 + 9.2 + 4.4 + 3.7 Additive inverse

Step 2) −8.3 + 4.4 + 9.2 + 3.7 Commutative property

Step 3) −8.3 + (4.4 + 9.2 + 3.7) Associative property

Step 4) −8.3 + 17.3


We can see that in step 1), Allen changed -4.4 into +4.4 using additive inverse. Notice that we are simplifying not eliminating -4.4 as we do in solving some equation. Hence using additive inverse is the wrong step.


Alen should have collect negative numbers together and positive numbers together.

Add the respective numbers then proceed to get the answer.


–8.3 + 9.2 – 4.4 + 3.7

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m_a_m_a [10]

Answer:

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Step-by-step explanation:

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b = -2-(4/3)(-3) = 2

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4/3x+2= -3/4x+2

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Plug x=0 into one of the equations to find y

y = 4/3(0) + 2

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coldgirl [10]

Answer:

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