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AURORKA [14]
2 years ago
7

Equation of the parabola in vertex form that passes through (4,-7) and has a vertex of (1,-6)

Mathematics
1 answer:
Alina [70]2 years ago
7 0

y = -\frac{1}{9}(x - 1)^2 - 6

Step-by-step explanation:

The vertex form of the equation for a parabola is given by

y = a(x - h)^2 + k

where (h, k) are the coordinates of the parabola's vertex. Since the vertex is at (1, -6), we can write the equation as

y = a(x - 1)^2 - 6

Also, since the parabola passes through (4, -7), we can use this to find the value for a:

-7 = a(4 - 1)^2 - 6 \Rightarrow -7 = 9a - 6

or

a = -\frac{1}{9}

Therefore, the equation of the parabola is

y = -\frac{1}{9}(x - 1)^2 - 6

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Step-by-step explanation:

P=2L+2W

38-8=30

If length is 8 less than twice the width and the perimeter is 38, then subtract 38-8 which is 30, then divide 30 by 2 to get 15.

P=2(4) +2(15)

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3 years ago
Which product is positive?
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Answer:

(Negative two-fifths) (Negative StartFraction 8 over 9 EndFraction) (one-third) (StartFraction 2 over 7 EndFraction)

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4 0
3 years ago
Read 2 more answers
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