2 years ago

Which polynomial is in standard form?

Mathematics

1 answer:

Stella [2.4K]2 years ago

3 0

B:
Explanation that equation is the B

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What is the value of A when we rewrite (32/5)^-2x as A^x

defon

Answer:

$(\dfrac{25}{1024})^x$

Step-by-step explanation:

The given expression is :

$(\dfrac{32}{5})^{-2x}$

We need to rewrite it in the form of $A^x$ .

We know that, $(\dfrac{1}{x})^{-a}=x^a$

So,

$(\dfrac{32}{5})^{-2x}=(\dfrac{5}{32})^{2x}\\\\=(\dfrac{5^2}{32^2})^x\\\\=(\dfrac{25}{1024})^x$

So, $A=\dfrac{25}{1024}$ . Hence, this is the required solution.

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We could stop here and have answered the question.

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