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Serga [27]
3 years ago
12

What is the value of y in the equation, 4(2y+1)=2(y-13)

Mathematics
1 answer:
Alik [6]3 years ago
4 0
I hope this helps you

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Sorry I don’t know that one but I recommend using the app photomath it really helps
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Use the relationships between the angles to find the value of x (please answer)
Varvara68 [4.7K]

Step-by-step explanation:

x + 15 \degree = 102 \degree \:  \\ (corresponding \:  \angle s) \\  \therefore \: x =  102 \degree -  15 \degree  \\  \huge \red { \boxed{\therefore \: x =  87 \degree}}

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Mona, Tabitha, and Reid are at a frozen yogurt shop. At the shop, frozen yogurt and toppings are charged by the ounce. The follo
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A.$0.45

B.$3.51

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3 years ago
Read 2 more answers
What the possible coordinates?
kicyunya [14]

Answer:

-15 and 9

Step-by-step explanation:

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7 0
3 years ago
While walking between gates at an airport, you notice a child running along a moving walkway. Estimating that the child runs at
tekilochka [14]

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

<h3>How to estimate the speed of the moving walkway relative to the airport terminal?</h3>

Let x be the speed of the walkway.

(2.8 + x) = speed of child moving in direction of the walkway

(2.8 - x) =  speed of child moving against the direction of the walkway

Travel time = distance/speed

Travel time of child moving in direction of walkway = 23/(2.8+x)

Total elapsed time given = 29s

23/(2.8 + x)+ 23 / (2.8-x) = 29

LCD = (2.8 + x)(2.8 - x)

23(2.8 - x) + 23(2.8 + x) = 29(2.8 + x)(2.8 -x)

simplifying the equation, we get

23*2.8-23x+23*2.8+23x=29(2.8^2-x^2)

23(2.8+2.8)/29=2.8^2-x^2

x^2=(2.8)^2-(23*5.6)/29)=3.4

x=\sqrt{3.4}=1.84m/s

Speed of walkway = 1.84 m/s

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

To learn more about Speed refer to:

brainly.com/question/4931057

#SPJ4

4 0
1 year ago
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