Answer:
8 one-dollar bills
3 five-dollar bills
2 ten-dollar bills
Step-by-step explanation:
Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13
x + 5y + 10z = 43
x = 4z
x + y + z = 13
x + 5y + 10z = 43
x + 0y - 4z = 0
x + y + z = 13
5y + 14z = 43
-y - 5z = -13
5y + 14z = 43
-5y - 25z = -65
-11z = -22
z = 2
x = 4z
x = 4*2 = 8
x + y + z = 13
8 + y + 2 = 13
10 + y = 13
y = 3
Answer:
The future value of this initial investment after the six year period is $2611.6552
Step-by-step explanation:
Consider the provided information.
A student desired to invest $1,540 into an investment at 9% compounded semiannually for 6 years.
Future value of an investment: 
Where Fv is the future value, p is the present value, r is the rate and n is the number of compounding periods.
9% compounded semiannually for 6 years.
Therefore, the value of r is: 
Number of periods are: 2 × 6 = 12
Now substitute the respective values in the above formula.




Hence, the future value of this initial investment after the six year period is $2611.6552
Your answer is C
It's hard to describe I did it all in my head but please trust me that C is correct