Question

Please help asap 30 pts

Answer 1

$\text{The reciprocal of}\ a\ \text{is equal}\ \dfrac{1}{a}\\\\a^{-1}=\dfrac{1}{a}$
$\dfrac{10b}{2b+8}\to\left(\dfrac{10b}{2b+8}\right)^{-1}=\dfrac{2b+8}{10b}$
$\boxed{Answer:\ C.\ \dfrac{2b+8}{10b}}$

Answer 2

Answer is C. because you flip the fraction upside down to find its reciprocal
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