2 years ago

Please help asap 30 pts

2 answers:

4 0

$\text{The reciprocal of}\ a\ \text{is equal}\ \dfrac{1}{a}\\\\a^{-1}=\dfrac{1}{a}$
$\dfrac{10b}{2b+8}\to\left(\dfrac{10b}{2b+8}\right)^{-1}=\dfrac{2b+8}{10b}$
$\boxed{Answer:\ C.\ \dfrac{2b+8}{10b}}$

sdas [7]2 years ago

3 0

Answer is C. because you flip the fraction upside down to find its reciprocal
((:

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