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evablogger [386]
2 years ago
13

Juan is 3 years younger than half his aunts age. If Juan is 27 years old, how old is his aunt?

Mathematics
2 answers:
Ugo [173]2 years ago
7 0
Juan’s aunt is 57 years old
Nikitich [7]2 years ago
5 0
Juan’s aunt is 24 27-3
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In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
Why did i get this wrong? What did i have to do to get the right answer?
aalyn [17]
Will u did your math wong 
6 0
3 years ago
Identify the translation of the figure with the vertices F(4,0), G(1,3), H(2,6) and I(4,2), along the vector ⟨−4,−4⟩. HELP PLEAS
mr Goodwill [35]

Answer:

  the last choice shown here: F'(0, -4), G'(-3, -1), H'(-2, 2), I'(0, -2)

Step-by-step explanation:

The translation vector tells you that the new coordinates are found by adding -4 to each of the old coordinates. When you realize that the answer choices differ in their values for H' and I', you can conclude that you only need to find one of those to determine the correct answer.

  H' = H + (-4, -4) = (2-4, 6-4) = (-2, 2) . . . corresponds to the last choice shown

_____

When you subtract 4 from each of the coordinates of the other points, you find they also match the last answer selection.

4 0
3 years ago
Someone answer urgent and if so I will mark brainliest
german

Answer:

the answer is D

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
2 lb/wk equals oz/day
inessss [21]

(2 lb/wk) x (16 oz/lb) x (1 wk/7 da) =

(2 x 16 x 1 / 7) (oz/da)  =  4.571 oz/da  (rounded)

7 0
3 years ago
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