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2 years ago

How are x-intercepts and y-intercepts alike? How are they different?

Mathematics

2 answers:

son4ous [18]2 years ago

8 0

Answer:

The x-intercepts are where the graph crosses the x-axis, and the y-intercepts are where the graph crosses the y-axis. An x-intercept is a point on the graph where y is zero, and a y-intercept is a point on the graph where x is zero.

Step-by-step explanation:

finlep [7]2 years ago

8 0

Answer:

See below.

Step-by-step explanation:

The x-intercept is where a line crosses the x-axis.

The y-intercept is where a line crossed the y-axis.

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Factors of 9.52? Please help. Google won’t tell

Elina [12.6K]

Answer:

9.52 x 1

4.26 x 2

4 x 2.38

Hope that helps

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2 years ago

The vertex of this parabola is at (2, -4). When the y-value is -1, the x-value is 3. What is the coefficient of the squared term

rjkz [21]

Answer:

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (2, - 4) , thus

y = a(x - 2)² - 4

To find a substitute (3, - 1 ) into the equation

- 1 = a(3 - 2)² - 4 ( add 4 to both sides )

3 = a

Thus

y = 3(x - 2)2 - 4 ← equation in vertex form

= 3(x² - 4x + 4) + 4

= 3x² - 12x + 12 + 4

= 3x² - 12x + 16 ← equation in standard form

with coefficient of x² term = 3

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3 years ago

Solve this equation for x: 2x^2 + 12x - 7 = 0

zhannawk [14.2K]

Answer:

x=0.5355 or x=-6.5355

First step is to: Isolate the constant term by adding 7 to both sides

Step-by-step explanation:

We want to solve this equation: $2x^2 + 12x - 7 = 0$

On observation, the trinomial is not factorizable so we use the Completing the square method.

Step 1: Isolate the constant term by adding 7 to both sides

$2x^2 + 12x - 7+7 = 0+7\\2x^2 + 12x=7$

Step 2: Divide the equation all through by the coefficient of $x^2$ which is 2.

$x^2 + 6x=\frac{7}{2}$

Step 3: Divide the coefficient of x by 2, square it and add it to both sides.

Coefficient of x=6

Divided by 2=3

Square of 3= $3^2$

Therefore, we have:

$x^2 + 6x+3^2=\frac{7}{2}+3^2$

Step 4: Write the Left Hand side in the form $(x+k)^2$

$(x+3)^2=\frac{7}{2}+3^2\\(x+3)^2=12.5\\$

Step 5: Take the square root of both sides and solve for x

$x+3=\pm\sqrt{12.5}\\x=-3\pm \sqrt{12.5}\\x=-3+ \sqrt{12.5}, $ or $x= -3- \sqrt{12.5}\\$x=0.5355 or x=-6.5355$

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2 years ago

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77julia77 [94]

Answer:

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Step-by-step explanation:

to start we can make an equation

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divide by 4

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