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2 years ago

I have more question then this

Mathematics

2 answers:

gregori [183]2 years ago

8 0

Answer:

A. A reflection over the x-axis

Lubov Fominskaja [6]2 years ago

7 0

Answer:

this is A, a reflection over the x axis

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Write the given roots to quadraatic equation

german

Answer:

It's like solving a quadratic, but in reverse, and in this case you'll arrive at x2+x−12=0

Explanation:

We're going to go "backwards" with this problem - normally we're asked to take a quadratic equation and find the roots. So we'll do what we normally do, but in reverse:

Let's start with the roots:

x=3, x=−4

So let's move the constants over with the x terms to have equations equal to 0:

x−3=0, x+4=0

Now we can set up the equation, as:

(x−3)(x+4)=0

We can now distribute out the 2 quantities:

x2+x−12=0

6 0

2 years ago

Two functions, function A and function B, are shown below:

elena-14-01-66 [18.8K]

The correct answer is:
<span>The rate of change of function B is greater than the rate of change of function A.

Hope this helps</span>

6 0

2 years ago

Read 2 more answers

Is the simplified form of 2 square root of 3 + 3 square root of 3 rational?

trasher [3.6K]

$2\sqrt3+3\sqrt3=(2+3)\sqrt3=5\sqrt3-\text{It's an irrational number}$

5 0

2 years ago

Find the perimeter of the triangle defined by the coordinates (7, 1), (-6, 1), and (10, 6). (Round to nearest tenth)

matrenka [14]

Answer:

$35.6\ units$

Step-by-step explanation:

we know that

The perimeter of triangle is equal to the sum of the length of the three sides

Let

$A(7, 1), B(-6, 1), C(10, 6)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(7, 1), B(-6, 1)$

substitute in the formula

$d=\sqrt{(1-1)^{2}+(-6-7)^{2}}$

$d=\sqrt{(0)^{2}+(-13)^{2}}$

$dAB=13\ units$

Find the distance BC

$B(-6, 1), C(10, 6)$

substitute in the formula

$d=\sqrt{(6-1)^{2}+(10+6)^{2}}$

$d=\sqrt{(5)^{2}+(16)^{2}}$

$dBC=16.8\ units$

Find the distance AC

$A(7, 1), C(10, 6)$

substitute in the formula

$d=\sqrt{(6-1)^{2}+(10-7)^{2}}$

$d=\sqrt{(5)^{2}+(3)^{2}}$

$dAC=5.8\ units$

Find the perimeter

$P=dAB+dBC+dAC$

$P=13+16.8+5.8=35.6\ units$

4 0

2 years ago

!GEOMETRY! does any get the questions for 8-10 and the other 10 as well. If i so please help, we have a test on these so please

denis23 [38]

Answer:

Answer:8: -4/7x+1 9: y=-x+1

Step-by-step explanation:

I dont knwo the rest just put into slope intercept form

7 0

2 years ago