he sides of a square are five to the power of two fifths inches long. What is the area of the square?
2 answers:
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Answer:
Step-by-step explanation:
The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:
And 0 for other case. Let X the random variable that represent "The number of years a radio functions" and we know that the distribution is given by:
We can assume that the random variable t represent the number of years that the radio is already here. So the interest is find this probability:
We have an important property on the exponential distribution called "Memoryless" property and says this:
Where a represent a shift and t the time of interest.
On this case then
We can use the definition of the density function and find this probability:
Answer:
a. About 96% of Spieth's drives travel at least 290 yards
b. The ball has to travel about 314.24 yards
Step-by-step explanation:
* Let us explain how to solve the problem
- The distance the ball travels can be modeled by distribution with
mean 304 yards and standard deviation 8 yards
a.
- Jordan would need to hit the ball at least 290 yards to have a clear
second shot that avoids a large group of trees
- We need to find the percent of Spieth's drives travel at least
290 yards
∵ The mean μ = 304 yards
∵ The standard deviation σ = 8 yards
∵ The distance x = 290
∵ P(x ≥ 290) = P(z ≥ z)
- We need to find z score
∵ z-score = (x - μ)/σ
∴ z = = -1.75
* Let us use the normal distribution table to find the corresponding
area of z = -1.75
∵ P(-z) = 1 - P(z)
∵ P(z ≥ -1.75) = 1 - 0.04006 = 0.95994
∴ P(x ≥ 290) = 0.96 = 96%
* <em>About 96% of Spieth's drives travel at least 290 yards</em>
b.
- On another golf hole, Spieth has the opportunity to drive the ball
onto the green if he hits the ball a distance in the top 10% of all
his drives
- We need to find how far the ball has to travel
- Let us find the z-score from the normal distribution table for the 10%
to the right or 90% to the left
∵ The area which equivalent to 0.9 ≅ 0.89973
∴ z = 1.28
∵ z-score = (x - μ)/σ
∴ 1.28 =
- Multiply both sides by 8
∴ 10.24 = x - 304
- Add 304 for both sides
∴ x = 314.24 yards
* <em>The ball has to travel about 314.24 yards</em>