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2 years ago

6

The Original Price of a 4ft×4ft Boards is $12.78, but when you buy 10 or more you pay $10.80. You only need 8, 4ft × 4ft Boards

Which would be the better deal?

1 answer:

Fittoniya [83]2 years ago

6 0

:) I don’t know the answer .

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X+y+(y-2)=60,1/2(x)(y-2)=120 what is x and y

Rudiy27

I think is this hopefully this helps

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3 years ago

Read 2 more answers

Hurry Need Help I Will Give Brainliest!!

Drupady [299]

Answer:

Measure of angle R: Measure of angle S:

42 degrees <em><u>90 - 42 = 48</u></em>

30 degrees <em><u>90 - 60 = 30</u></em>

84 degrees <em> </em><em><u>90 - 84 = 6</u></em>

<em><u>Complimentary angles are angles whose sum is 90 degrees</u></em>

7 0

2 years ago

Read 2 more answers

Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1

elena-s [515]

Answer:

a) $P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

b) $P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

c) $0.75 =\frac{0.83}{1+e^{-0.2n}}$

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

d) If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

$P(n) = \frac{0.83}{1+e^{-0.2t}}$

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

$P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

So the number of correct reponses after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

$P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

$0.75 =\frac{0.83}{1+e^{-0.2n}}$

And we can rewrite this expression like this:

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

Now we can apply natural log on both sides and we got:

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

5 0

3 years ago

Scott is playing a game in which he rolls a number cube with faces numbered 1through 6 and spins the spinner shown below one tim

defon

Solution:

The total number of possiblities rolling a number cube with faces numbered 1 to 6 is;

And the total number of possibilities spining the spinner is;

The number of possibility where outcome on the cube is greater than 2 is;

$4$

And the number on the spinner less than 9 is;

$2$

Hence, the unique combination is;

$4\times2=8$

CORRECT OPTION: A

7 0

11 months ago

ehidna [41]

Answer:

A. the distance between points W and X

Step-by-step explanation:

<u><em>Looking for the distance of 5 units</em></u>

A. the distance between points W and X

-3 - (-8) = -3 + 8 = 5
Correct

B. the distance between points X and Y

1 - (-3) = 1 + 3 = 4 < 5
Incorrect

C. the distance between points X and Z

5 - (-3) = 5 + 3 = 8 > 5
Incorrect

D. the distance between points Y and Z

5 - 1 = 4 < 5
Incorrect

7 0

2 years ago