Just multiple them together and u get 693
The matrix equation has no solution because the same matrix of equal magnitude and opposite in nature is been added to it.
Given to us
A + [11 17 -8 13] = [0 0 0 0]
<h3>What is the value of matrix A?</h3>
We know that the given matrix will give values as zero if the same matrix is been deducted from it, therefore,
A + [11 17 -8 13] = [0 0 0 0]
A = [0 0 0 0] - [11 17 -8 13]
A = [-11 -17 +8 -13]
Thus, the matrix is equal to [-11 -17 +8 -13].
<h3>why this matrix equation has no solution?</h3>
The matrix equation has no solution because the same matrix of equal magnitude and opposite in nature is been added to it, therefore, [11 17 -8 13] is been added to it.
Thus, the sum of the two matrices has no solution.
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Answer:
x = - 7, y = 6
Step-by-step explanation:
7x + 7y = - 7 -----> equation 1
- 10x - 7y = 28 -----> equation 2
Add equations 1 & 2,
7x + 7y = - 7
- 10x - 7y = 28
___________
- 3x + 0 = 21
- 3x = 21
x = 21 / - 3
x = - 7
Substitute x = - 7 in equation 1,
7x + 7y = - 7
7y + 7x = - 7
7y + 7 ( - 7 ) = - 7
7y - 49 = - 7
7y = - 7 + 49
7y = 42
y = 42 / 7
y = 6
Answer: D
Step-by-step explanation: By using SOH for sin A, 'S' being sin, 'O' being opposite side of angle A and 'H' being the hypotenuse which is the longest part of the triangle you would find that 15 is opposite from Sin A and 17 the hypotenuse, 15/17.
For cos A you would use CAH, C= cos, A which is the adjacent of the triangle located next to angel A which is 8, and H= hypotenuse (also note that the hypotenuse never changes even if the angle may be different) CAH would be cos A = 8/17
The side length is 5 units, and the area is 25 square units
<h3>What are areas?</h3>
The area of a shape is the amount of space it occupies
<h3>What is the area of a square</h3>
The area of a square is the product of its dimensions
From the graph, the coordinates of the square can be assumed to be:
The side length of the square is then calculated using the following distance formula
So, we have:
The area of the square is the calculated as:
This gives
Hence, the side length is 5 units, and the area is 25 square units
See attachment for the diagram of the shape
Read more about areas at:
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