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3 years ago

The function g(x) is a transformation of the cube root parent function, f(x) =3^square root x

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

6 0

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AnnyKZ [126]

An even prime number would be 4,8,10

3 0

3 years ago

At a harvest 16 ears are being picked foot every 18 peppers. If 19 peppers have been picked, how many eats of corn have been pic

ExtremeBDS [4]

The number of eats of corn which have been picked is; 16.9 corns.

<h3>How many eats of corn have been picked?</h3>

According to the question; 16 eats of corn are being picked foot every 18 peppers. In essence, the ratio of corns to peppers is; 16/18.

Hence, it follows that the number of corns which corresponds to 19 peppers been picked can be evaluated as follows;

16/18 = x/19

x = (19×16)/18

x = 16.9 eats of corn.

Read more on ratios;

brainly.com/question/13513438

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2 years ago

PLEASE ANSWER I WILL GIVE BRAINLIEST

Yuri [45]

Answer:

Step-by-step explanation:

Replace the variables with their corresponding numbers.

y-x/z 64-4/3 60/3 20

5 0

3 years ago

Explain how you can rewrite the equation n+8=24 so that it involves subtraction rather than addiction

Vinil7 [7]

Answer:

n = 24 - 8.

Step-by-step explanation:

n + 8 = 24

Subtract 8 from each side:

n + 8 - 8 = 24 - 8

n = 24 - 8.

8 0

3 years ago

Read 2 more answers

A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs

LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

$h=\frac{400}{\pi r^2}$

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: $h=\frac{400}{\pi r^2}$

Therefore:

$C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})$

$C(r)=0.12\pi r^2+\frac{24}{r}$

$C(r)=\frac{0.12\pi r^3+24}{r}$

The minimum cost occurs when the derivative of the Cost =0.

$C^{'}(r)=\frac{6\pi r^3-600}{25r^2}$

$6\pi r^3-600=0$

$6\pi r^3=600$

$\pi r^3=100$

$r^3=\frac{100}{\pi}$

$r^3=31.83$

r=3.17 cm

Recall that:

$h=\frac{400}{\pi r^2}$

$h=\frac{400}{\pi *3.17^2}$

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

3 0

3 years ago