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Hatshy [7]
2 years ago
7

Mr. Smith asked his students whether they prefer to go to the museum or the zoo for a field trip. He found that 35% of the stude

nts prefer to go to aa museum, 45% prefer to go to the zoo, and the rest have no preference. What is the Ratio of students who have no preference to the students who prefer to go to the museum?
Mathematics
1 answer:
PtichkaEL [24]2 years ago
4 0

Answer: The answer is C 4:7

Step-by-step explanation:

Hopes this helps

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HELP PLEASE AND THANK YOU 1JAAB
Dafna1 [17]

Answer:

\bold{Q1}\ side\ BD\\\\\bold{Q2}\ \angle5\ \leftrightarrow\ \angle6\\\\\bold{Q3}\ \triangle TAP\\\\\bold{Q4}\ \triangle APT

Step-by-step explanation:

For Q1 and Q2

\text{If}\ AB\cong AC,\ BD\cong CD,\ RSTU\ \text{is a parallelogram (rectangle)},\ \text{then}\\\\\angle 1\ \leftrightarrow\ \angle2\\\angle3\ \leftrightarrow\ \angle4\\\angle C\leftrightarrow\ \angle B\\\angle 5\ \leftrightarrow\ \angle6\\\angle7\ \leftrightarrow\ \angle 8\\\angle R\ \leftrightarrow\ \angle T\\\angle S\ \leftrightarrow\ \angle U

\overline{AB}\ \leftrightarrow\ \overline{AC}\\\overline{BD}\ \leftrightarrow\ \overline{CD}\\\\\overline{RS}\ \leftrightarrow\ \overline{TU}\\\overline{ST}\ \leftrightarrow\ \overline{UR}

For Q3 and Q4

O\ \leftrightarrow\ T\\B\ \leftrightarrow\ A\\R\ \leftrightarrow\ P\\\\E\ \leftrightarrow\ X\\F\ \leftrightarrow\ W\\D\ \leftrightarrow\ T

4 0
3 years ago
Find dy/dx by implicit differentiation. y cos x = 5x2 + 3y2
lbvjy [14]
Step 1:
Start by putting \frac{d}{dx} in front of each term

\frac{d}{dx}[y cos x]= \frac{d}{dx}[5x^2]+ \frac{d}{dx}[ 3y^2]
-----------------------------------------------------------------------------------------------------------------
Step 2:

Deal with the terms in 'x' and the constant terms
\frac{d}{dx}[ycosx]= 10x+ \frac{d}{dx} [3y^2]
----------------------------------------------------------------------------------------------------------------
Step 3:

Use the chain rule for the terms in 'y'
\frac{d}{dx}[ycosx]=10x+6y \frac{dy}{dx}
--------------------------------------------------------------------------------------------------------------
Step 4:

Use the product rule on the term in 'x' and 'y'
(y) \frac{d}{dx} cos x+(cos x) \frac{d}{dx}y =10x+6y \frac{dy}{dx}

y(-siny)+(cosx) \frac{dy}{dx} =10x+6y \frac{dy}{dx}
--------------------------------------------------------------------------------------------------------------

Step 5:

Rearrange to make \frac{dy}{dx} the subject
-y sin(y)+cos(x) \frac{dy}{dx} =10x+6y \frac{dy}{dx}
cos(x)  \frac{dy}{dx}-6y \frac{dy}{dx}=10x+y sin(y)
[cos(x) - 6y]  \frac{dy}{dx}=10x + y sin(y)
\frac{dy}{dx}= \frac{10x+ysin(y)}{cos(x)-6y} ⇒ Final Answer


5 0
4 years ago
What’s the answer F(x)=3/x-2
Oksana_A [137]
(-infinity,2)U(2,infinity)
{x/xnot=2}
this is what I found
7 0
3 years ago
A paper store sells wrapping paper rolls and bags. In the spring, they order a ratio of 3:7 in wrapping paper bags in the spring
Maru [420]

If it can be assumed that the total number paper and bags is the same for both orders, then:

#bags ordered in the spring=7*(150/3)=350, so the total of both is 150+350=500. A 5:5 ratio means that the wrapping paper and bags were bout in equal quantities. That means 500/2=250 for each.

6 0
3 years ago
What is the name for a measurement of how two variables are related?
lorasvet [3.4K]

Answer:

correlation

Step-by-step explanation:

Correlation is a statistical technique that is used to measure and describe a relationship between two variables.

7 0
3 years ago
Read 2 more answers
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