What fraction is equivalent to .7?

Mathematics

2 answers:

solong [7]2 years ago

7 0

Answer:

7/10

Step-by-step explanation:

$0.7 =\dfrac{7}{10}$

Nuetrik [128]2 years ago

3 0

Your answer should be 7/10 and this can not be simplified!

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I kneed to know what 2/3 - 9/10 is so i can do the rest of my homework

Illusion [34]

Answer:

-7/30

Step-by-step explanation:

So you need to make the denominators the same number so that you can just subtract the numerators.

(10) 2/3 - (3) 9/10

20/30 - 27/30

-7/30

6 0

2 years ago

Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Thepotemich [5.8K]

$\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

Explanation

$\frac{1}{a+bi}=c+di$

Step 1

multiplicate by the conjugate

$\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}$

notice that

$\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\ \end{gathered}$ $\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

I hope this helsp you

6 0

1 year ago

The question is in the screenshot

Sidana [21]

Answer:

b. -36/77

Step-by-step explanation:

As 0 < x < $\pi$ /2 => tan x > 0