Solve the equation 2x

1) prove that the circumcenter of an equilateral triangle is the same as its centroid i) calculate the length of the side of an

Juliette [100K]

Answer:

The complete explanation and solution is attached below:

Explanation:

4 0

3 years ago

G(X)= 6X - 3<br> What is g-1 (9)

harkovskaia [24]

G(X)=6X-3
Y=6X-3
X=6Y-3
X+3=6Y
Y=(X+3)/6
G^-1(9)=(X+3)/6
G^-1(9)=(9+3)/6
G^-1(9)=2

6 0

3 years ago

The length of a table is 6 feet. On a scale drawing, the length is 2 inches. Write three possible scales for the drawing.

Rus_ich [418]

A possible scale for the drawing can be
1 inches : 3 feet.
2 inches : 6 feet
or 3 inches to 9 feet
or 0.5 inches to 1.5 feet.

Hope this helps :)

6 0

3 years ago

Given points A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1), which of the following proves that

damaskus [11]

Similar triangles may or may not have equal side lengths

Triangles ABC and DEF are similar by SSS theorem

<h3>How to determine the similarity statement</h3>

The coordinates of the two triangles are:

A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1)

Calculate the lengths of both triangles using the following distance formula

$d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}$

For triangle ABC, we have:

$AB = \sqrt{(0 -4)^2 + (0 -0)^2} = 4$

$BC = \sqrt{(4 -0)^2 + (0 -2)^2} = 2\sqrt 5$

$CA = \sqrt{(0 -0)^2 + (0 -2)^2} = 2$

For triangle DEF, we have:

$DE = \sqrt{(0 -2)^2 + (0 -0)^2} = 2$

$EF = \sqrt{(2 -0)^2 + (0 -1)^2} = \sqrt 5$

$FD = \sqrt{(0 -0)^2 + (1 -0)^2} = 1$

Divide corresponding sides of the triangles to calculate the scale factor k

$k = \frac{AB}{DE} = \frac{BC}{EF} = \frac{CA}{FD}$

This gives

$k = \frac{4}{2} = \frac{2\sqrt 5}{\sqrt 5} = \frac{2}{1}$

Evaluate the quotients

$k = 2 = 2 = 2$

Since the quotients are equal, then the triangles are similar

Hence, triangles ABC and DEF are similar by SSS theorem

Read more about similar triangles at:

brainly.com/question/14285697

3 0

2 years ago

Suppose △LPO ≅ △HJU.<br> What is the corresponding congruent parts for each segment or angle?

SashulF [63]

Answer:

NG ( first and last letter of NBG) = WS ( first and last letter of WTS).

BG = TS

G = S

N =W or NG = WS; BG = TS; G = S; N = W.

Step-by-step explanation:

We use the congruence statement to answer these questions. From the way the congruence statement is written, we can see that N = W (they are in the same relative position in the congruence statement). We also see that G and S are in the same relative position, so G = S.

Since N = W and G = S, this means that NG = WS.

From the congruence statement we can also see that B = T (they are in the same relative position). Since G = S, this means that BG = TS.

5 0

3 years ago

Solve the equation 2x - 4 = 12