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3 years ago

HELP DUE IN 20 MINS!!!!!!

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

5 0

Answer:

10 miles

Step-by-step explanation:

Set up a proportion: $\frac{15}{1.5} = \frac{x}{1}$
Cross multiply, then divide: 15 × 1 = 15, 15 ÷ 1.5 = 10
So, Jessica can run 10 miles in 1 hour

I hope this helps!

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f(x)=8−4x−x3 g(x)=x2+7x−9 Find f(x)+g(x). Select one: a. x3+x2+3x−1 b. −x3+x+3x−1 c. −x3+x2+11x−9 d. 8x2+3x−9x3

vovangra [49]

Answer:

Step-by-step explanation:

We are given the two functions:

$f(x) = 8 - 4x - x^3\text{ and } g(x) = x^2 + 7x - 9$

And we want to find:

$f(x) + g(x)$

Substitute:

$= (8 - 4x - x^3) + (x^2 + 7x - 9)$

Rewrite:

$= (-x^3) + (x^2) + (7x - 4x) + (8 - 9)$

Combine like terms:

$= -x^3 + x^2 +3x -1$

In conclusion:

$f(x) + g(x) = -x^3 + x^2 +3x -1$

Hence, our answer is B.

7 0

3 years ago

A pole that is 3.1m tall casts a shadow that is 1.29m long. At the same time, a nearby building casts a shadow that is 44.75m lo

Mkey [24]

Let b=height of building. By similar triangles we can say:

b/44.75=3.1/1.29

b=44.75*3.1/1.29

b≈107.54

b≈108 meters (to the nearest whole meter)

8 0

4 years ago

Read 2 more answers

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0

3 years ago

If k is an integer and r = k2 + 3k + 9, which of the following statements about r must be true for all values of k?

Andru [333]

9514 1404 393

Answer:

D. None

Step-by-step explanation:

If one of these is true for all values of k, we can see it for k=1.

r = 1² +3·1 +9 = 13

This value is not even, not divisible by 3, and not the square of an integer.

None of the offered statements about r is true.

8 0

3 years ago

How much does 3.25m of lace cost if 0.8m costs $5.60?

lidiya [134]

Answer:

Step-by-step explanation:

3.25/.8=4.0625

multiply that by 5.6

$22.75 is your answer

8 0

3 years ago