Answer: $20
Step-by-step explanation:
Let 'x' be the cost of a ticket at Haynes
Let 'y' be the cost of a ticket at Valley
Since the total cost from both schools are the same, we can write it as:
Since the cost of tickets at Valley was $5 less than Haynes, we can write it as:
Now we have two equations, we can use to substitute into the other expression:
we substitute y in this equation with the other equation
Therefore the cost of the ticket at Haynes is $20 and the cost of the ticket at Valley is $15.
Answer:
1/3
Step-by-step explanation:
im not sure what answer you were looking for but hope this helps
6 1/2
First you find a common denominator. 1/4 = 3/12 and 1/3 = 4/12.
3/12 + 4/12 + 11/12 = 18/12.
18/12 = 6 6/12 = 6 1/2
For 1 multiply both sides by 3 which gives you 3y-y=12. Then combine like terms 2y=12. Lastly divide both sides by 2 and you get y=6. And for 3 first multiply both sides by 4 which gives you 6y-32=y+8. After that combine like terms 6y-y-32=8. Now add the equation together 5y=40 and then divide by 5 and get y=8
The correct answer is: [C]: " p = 6.25 h " .
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Explanation:
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It is clear that "pay" is a function of "hours worked" ;
So, we can eliminate: "Choice [B]: " h = <span>6.25p" .
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Try, Choice [A]: " </span>p = h + 12.5 " ; and 14.50 ≠ 12.50 ; (12.50 is the amount shown in the table. So, we can already eliminate "Choice [A]".
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Now that we have eliminated choices [A] and [B];
we are left with choices: [C] and [D]:
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Consider choice [C]: " </span><span>p = 6.25h " ;
</span> when "h = 2" ; does: "p = 12.5" (as shown on table)?? ;
i.e. " 12.5 =? 6.25 * (2) ?? Yes! This choice is a POSSIBILITY.
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Consider choice [D]: " p = 12.5h" .
When "h = 2, does "p = 12.5" (as shown on table)? No!
→ We can see from this very answer choice
(the equation itself) that when "h = 2" ;
the value of "p" is DOUBLE [that of "12.5"].
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The correct answer is: Answer choice: [C]: " <span>p = 6.25 h " .
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