Answer: a) 0.0792 b) 0.264
Step-by-step explanation:
Let Event D = Families own a dog .
Event C = families own a cat .
Given : Probability that families own a dog : P(D)=0.36
Probability that families own a dog also own a cat : P(C|D)=0.22
Probability that families own a cat : P(C)= 0.30
a) Formula to find conditional probability :
(1)
Similarly ,

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792
b) Again, using (2)

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264
Answer:
A) 1/3 D) 13/39 E) 14/42
Step-by-step explanation:
hope this helps. brainliest please.
The first term is 2 and the common ratio = -8/2 = -4
S7 = 2 * (-4)^7 - 1
------------- = 6554 answer
-4-1
It takes 6 seconds for it to hit the ground.
0 = -5x²+20x+60
We can solve this by factoring. First factor out the GCF, -5:
0 = -5(x²-4x-12)
Now we want factors of -12 that sum to -4. -6(2) = -12 an -6+2 = -4:
0 = -5(x-6)(x+2)
Using the zero product property, we know that either x-6=0 or x+2=0; this gives us the answers x=6 or x=-2. Since we cannot have negative time, x=6.
Answer:
75%
Step-by-step explanation:
44*75% = 33