The average maximum and minimum values of a formula
Next time, please include the directions for the problem you post. Here it appears that you have given the values of I, P and t two times each.
Unfortunately, I have to guess what you're looking for.
Assuming that I=$26.25 is the interest earned on Principal P=$500, and that t is the length of time over which the Principal earns interest,
I=Prt. With I, P and t given, it's obvious that our job is to find the annual interest rate, r. So, from I=Prt, we get
$26.25 = $500 (r) (1.5 years) Solve this for the interest rate, r.
Express r both as a decimal fraction and as the equivalent percentage.
Answer:
The average rate of change for the given function in the interval (-5, -1) is 0 (zero)
Step-by-step explanation:
The average rate of change of a function over an interval is the quotient between the difference between the function evaluated at the ends of the interval divided by the length of the interval. That is for our case:
the average rte of change of h(t) in the interval (-5, -1) is:
so we find:
then the average rate of change becomes:
I think it’s D I hope this helps!!!
