Answer:
The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the z-score that has a p-value of
.
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.
This means that 
95% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
From what I know this graph looks like that of a modulus function except it's shifted 1 unit to right and 1 unit below the origin.
So the original equation must be:
y = |x|
And the transformed equation (aka the equation if this graph) must be,
y+1 = |x| -1
y = |x| -2
The best estimate of the sum of the expression given is 
What is a Fraction ?
A fraction is written as p/q , where q
0
It is asked to determine the sum of the fraction
31/4 + 17/3 + 8/18
Taking the LCM of 4 , 3 , 18
LCM of 4 , 3 ,18 is 36
Therefore

(279+204+16) /36
499 / 36

Therefore the best estimate of the sum of the expression given is
.
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