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3 years ago

What equation models the line that goes through the point (12,3) and has a slope of -1/3

Mathematics

1 answer:

vivado [14]3 years ago

5 0

Answer:

y= -1/3x+7

Step-by-step explanation:

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At a sandwich shop they offer 3 kinds of bread, 5 kinds of meat, and 3 kinds of cheese. Each type of sandwich has a combination

horrorfan [7]

The amount of different combos possible would be 165 // Hope this helped, comment below for any clarifications // Brainliest ;) Thanks!! //

8 0

3 years ago

PLEASE HELP ME FAST! Thank you!!

likoan [24]

X=26

This is because KM is equal to 104 and 104 divided by 4 (due to there being 3x and x)is equal to 26 and if you do 104 + 256 you will get 360

6 0

3 years ago

If BC= 48 cm and sin

erastovalidia [21]

Using relations in a right triangle, it is found that the length of AC is of 14 cm.

<h3>What are the relations in a right triangle?</h3>

The relations in a right triangle are given as follows:

The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.

The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.

The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.

Researching this problem on the internet, we have that:

The opposite leg to angle A is of 48 cm.

sin(A) = 0.96.

Hence the hypotenuse is found as follows:

sin(A) = 48/h

0.96 = 48/h

h = 48/0.96

h = 50 cm.

The length of side AC is the other leg of the triangle, found using the Pythagorean Theorem, hence:

$x^2 + 48^2 = 50^2$

$x^2 = \sqrt{50^2 - 48^2}$

x = 14 cm.

More can be learned about relations in a right triangle at brainly.com/question/26396675

#SPJ1

6 0

2 years ago

If f(x) = arcsinx, then f' (√3/2)=

Irina-Kira [14]

You can either use the inverse function theorem or compute the general derivative using implicit differentiation. The first method is slightly faster.

The IFT goes like this: if f(x) is invertible and f(a) = b, then finv(b) = a (where "finv" means "inverse of f").

By definition of inverse functions, we have

f(finv(x)) = finv(f(x)) = x

Differentiating both sides of the second equality with respect to x using the chain rule gives

finv'(f(x)) * f'(x) = 1

When x = a, we get

finv'(b) * f'(a) = 1

finv'(b) = 1/f'(a)

Now let f(x) = sin(x), which is invertible over the interval -π/2 ≤ x ≤ π/2. In the interval, we have sin(x) = √3/2 when x = π/3. We also have f'(x) = cos(x).

So we take a = π/3 and b = √3/2. Then

arcsin'(√3/2) = 1/cos(π/3) = 1/(1/2) = 2

4 0

3 years ago

Find (f*f)(3)<br><br> f(x)=x^2-x<br><br> A. 30<br> B. 6<br> C. 33<br> D. -6

Tems11 [23]

Answer:

Step-by-step explanation:

$(f\circ f)(x)=f\bigg(f(x)\bigg)\\\\f\bigg(f(3)\bigg)\\\\\text{Calculate}\ f(3):\\\\f(3)=3^2-3=9-3=6\\\\f\bigg(f(3)\bigg)=f(6)=6^2-6=36-6=30$

6 0

4 years ago