The correct answer is: Glycogen phosphorylase would remain phosphorylated and retain some activity.
Glycogen phosphorylase is directly involved in the regulation of glucose levels since it is a glucose sensor in liver cells: when glucose levels are low, phosphorylase is active and it has PP1 bound to it (phosphatase activity of PP1 is prevented). Therefore, there phosphorylase a will accelerate glycogen breakdown.
The answer can be either multicellular organisms or the scientific word of Eukaryotes.
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In the hydrologic cycle, after water precipitates to the surface, it can return to the atmosphere by processes of evaporation.
Answer:
Cross the green-pod plant with a yellow-pod plant.
Explanation:
To determine the zygosity of a particular individual, the best way is to cross it with a phenotypically recessive individual.
Such a cross in which an individual with unknown zygosity possessing a dominant trait is crossed with an individual possessing a recessive trait is termed as a test cross.
Therefore, in the given situation the zygosity of the green pod needs to be determined and the green pod is a dominant character. Further, it is given that a yellow pod is a recessive trait, therefore a test cross can be performed between the green pod and yellow pod, and then the offsprings can be observed.
if the offsprings are all phenotypically dominant then the green pod is homozygous and if there are phenotypically recessive offspring also present then the green pod is heterozygous genotypically.
