<h3>x = 21/5</h3>
Step-by-step explanation:
<h3>___________________________</h3>
<h3>Given →</h3>
5x:9 = 7:3
<h3>So,</h3>
→ 5x/9 = 7/3
→ x = (7 × 9)/(3 × 5)
→ x = 21/5
<h3>___________________________</h3>
<h3>Hope it helps you!!</h3>
For each number,there is a 16 probability of rolling it (so 16 for the 1 and also 16 for the 4)
Hope This Helps
#1: "AD" is congruent to "BC" | given
Answer:
a
Step-by-step explanation:
Answer:
We accept H₀. We do not have argument to keep the claim that the mean breaking strength has increased
Step-by-step explanation:
Normal Distribution
Population Mean μ₀ = 1850 pounds
Standard Deviation σ = 90 pounds
Type of test
Null Hypothesis H₀ ⇒ μ = μ₀
Alternative Hypothesis Hₐ ⇒ μ > μ₀
A one tail test (right)
n = 21 as n < 30 we use t-student table
degree of fredom 20
t = 2.845
Sample mean μ = 1893
Then, we compute t statistics
t(s) = [ 1893 - 1850 ] / 90/ √n
t(s) = 43 * 4,583 / 90
t(s) = 197,069 / 90
t(s) = 2,190
And we compare t and t(s)
t(s) = 2.190
t = 2.845
Then t(s) < t
We are in the acceptance zone, we accept H₀
