The answer is 0
Let me tell you why
first plug in the numbers
.5(18+14)-(18-14)^2
(9+7)-(4)^2
16-16
0
55% of 1800 = 0.55(1800) = 990...so there are 990 girls in the school
30% of 990 = 0.30(990) = 297...so there are 297 girls who take the bus
<span>Let R=A AND (NOT B)] OR (NOT B)
If A=T, B=T
then ~B=F,
A and ~B = F
So R=F
If A=T,
B=F
~B=T
A and ~B=T
so (A and ~B) or ~B = T
etc.</span>
both the surface areas of the green and blue figures?
Answer:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.
Step-by-step explanation:
In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.
Let u = 1 + sin(x).
This means du/dx = cos(x). This implies dx = du/cos(x).
Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.
∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))
= ∫(u^(-1/2) * du). Integrating:
(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.
Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!
