The complete question in the attached figure
Part A) find the perimeter
[perimeter of the garden]=[perimeter square 1]+[perimeter a quarter circle]+[perimeter square 2]
[perimeter square 1]=5+5+5-----> 15 ft
[perimeter square 2]=5+5+5-----> 15 ft
[perimeter a quarter circle]=(2*pi*r)/4------> 2*pi*5/4-----> 7.85 ft
[perimeter of the garden]=[15]+[7.85]+[15]-------> 37.85 ft
the answer Part A) isthe perimeter of the garden is 37.85 ftPart B) Find the area of the garden
[Area of the garden]=[Area square 1]+[Area a quarter circle]+[Area square 2]
[Area square 1]=5*5-----> 25 ft²
[Area square 2]=5*5-----> 25 ft²
[Area a quarter circle]=(pi*r²)/4------> pi*5²/4-----> 19.625 ft²
[Area of the garden]=[25]+[19.625]+[25]-------> 69.625 ft²
the answer Part B) isthe Area of the garden is 69.625 ft²
Answer:
The student is incorrect because I I or absolute value would make the -9 to positive 9.
Step-by-step explanation:
-9<4
on a numberline
-9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4
but the absolute value of -9 (or) |–9|
is actually positive 9
9>4
on a number line
4 5 6 7 8 9
Answer:
I think the answer is O 56 × (-14)
1 = Hundred tens of thousandths.
0 = tens of thousandths.
6 = thousandths.
5 = hundredths.
3 = tenths.
4 = units.
In this question, the number of seat of A equal the number total seats on B and C. The equation would be:
A=B=C
Total seat= A+B+C= A+A+A=3A
The total revenue for the stadium is <span>$1,193,400. Then the total number of the seat would be:
revenue= total seats*price per seat
</span>$1,193,400= A * $30 + B*24 + C*18
$1,193,400= A * $30 + A*24 + A*18
$1,193,400= A * $72
A= $1,193,400/ 72
A= 16575
Each section hold 16575 seats