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GarryVolchara [31]
3 years ago
9

Jambi can 148 mile bicycle trip to build up stamina for a triathlon competition unfortunately his bicycle chain broke so he fini

shed walking the trip walking the whole trip took five hours of jam walks at a rate of 3 mph and rides at 41 mph find the amount of the time he spent on the bicycle
Mathematics
1 answer:
Jobisdone [24]3 years ago
5 0

Walking at 3mph he wouldve walked 15 miles in 5 hours, leaving 133 miles on bike.

133/41=3.24390244hours on the bike

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Mathematics, Help, not sure about my answer on this one
olga nikolaevna [1]

Answer:

F. 2 1/9

Step-by-step explanation:

Step 1: Substitute q

r = 3(\frac{1}{3^n} )+2

When you plug in <em>n</em> = 1, 2, 3:

n(1) = 3

n(2) = 2.11111

n(3) = 2.3333

So our answer is F.

3 0
3 years ago
Use the three steps to solve the problem.
Oksana_A [137]

Answer:

If the second of the three numbers is  

n

, then the first and third are  

n-  1 and  n + 1 , so we find: 117 = ( n − 1 ) + n + ( n + 1 ) = 3n  

Dividing both ends by  

3  we find: n = 117/  3   = 39

So the three numbers are:

38 , 39 , 40

Step-by-step explanation : I hope it helps please don't forget to mark me brainliest  .  :)

4 0
2 years ago
Read 2 more answers
Which equation has the solutions x=1+/- 5?
nikitadnepr [17]

Answer:

x^{2} -2x-4=0

Solving Steps

Use the quadratic formula

x=\frac{-(-2)(+/-)\sqrt{(-2)^2-4*1*(-4)} }{2*1}

Multiply / Remove the parentheses / Evaluate

x=\frac{2(+/-)\sqrt{4+16} }{2}

Calculate

x=\frac{2(+/-)\sqrt{20} }{2}

Separate the solutions

x=\frac{2(+/-)2\sqrt{5} }{2} \\x=\frac{2-2\sqrt{5} }2}

Simplify

x=1+\sqrt{5} \\x=1-\sqrt{5}

4 0
2 years ago
Which pair shows equivalent expressions?
Murrr4er [49]

Answer:

2(2/5x+2)=4x/5+4

Step-by-step explanation:

2(2/5x+2)=4x/5+4

4x/5 +4=4x/5 +4

7 0
3 years ago
We want to find the zeros of this polynomial:
fredd [130]

Answer:

x = -3 and x = -3/2

Step-by-step explanation:

After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:

p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>

p(x) = x^2(2x+3) <u>-9(2x+3)</u>

Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:

p(x) = (x^2 - 9)(2x+3)

Factor it once more because there's a difference of squares:

p(x) = (x+3)(x-3)(2x+3)

Now just plug in whatever makes the each bracket equal 0:

x = -3, x = 3, and x = -3/2

Those are your zeros.

8 0
2 years ago
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