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GarryVolchara [31]
3 years ago
9

Jambi can 148 mile bicycle trip to build up stamina for a triathlon competition unfortunately his bicycle chain broke so he fini

shed walking the trip walking the whole trip took five hours of jam walks at a rate of 3 mph and rides at 41 mph find the amount of the time he spent on the bicycle
Mathematics
1 answer:
Jobisdone [24]3 years ago
5 0

Walking at 3mph he wouldve walked 15 miles in 5 hours, leaving 133 miles on bike.

133/41=3.24390244hours on the bike

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Quadrilateral LMNO is similar to quadrilateral PQRS. Find the measure of side QR.
dalvyx [7]

Answer:

The measure of the side QR is 8.8.

Step-by-step explanation:

Since LMNO \sim PQRS, then SP \propto OL, RS \propto ON, RQ \propto MN and QP \propto LM. From figure we have the following relationship:

k = \frac{OL}{SP} = \frac{ON}{RS} = \frac{MN}{QR} = \frac{ML}{QP} (1)

Where k is the proportionality ratio.

If we know that SP = 13, OL = 55, MN = 37, then the measure of side QR is:

k = \frac{OL}{SP} (1b)

k = \frac{55}{13}

k = \frac{MN}{QR}

QR = \frac{MN}{k} (1c)

QR = \frac{37}{\frac{55}{13} }

QR = 8.745

The measure of the side QR is 8.8.

4 0
3 years ago
Gcf of -15xyz, -55xy²,- 55yz
GalinKa [24]

Answer:

-5y

Step-by-step explanation:

15 = 3×5

55 = 5×11

-15xyz = -1 × 3 × 5 × x × y × z

-55xy² = -1 × 5 × 11 × x × y²

-55yz = -1 × 5 × 11 × y × z

HCF = multiply all common factors with the lowest power amongst all 3 expressions

HCF = -1 × 5 × y = -5y

3 0
1 year ago
How do you find a value of x so that f(x) = 7?
DiKsa [7]

Answer:

When f(x) = 7, x is equal to 5.

Step-by-step explanation:

When looking at this graph, we are looking for where the line hits a point where y is equal to 7. That's because f(x) is essentially the same thing as y.

The point in which the graph hits y = 7 is (5, 7). This means the x value we need is 5.

5 0
3 years ago
To three decimal places, find the average value of f(x) = 2x2 + 3 on the interval [0, 2].
salantis [7]
The formula for the average value of a function is \frac{1}{b-a}  \int\limits^b_a {f(x)} \, dx where b is the upper bound and a is the lower.  For us, this formula will be filled in accordingly.  \frac{1}{2}  \int\limits^2_0 {(2x^2+3)} \, dx.  We will integrate that now: \frac{1}{2}[ \frac{2x^3}{3}+3x] from 0 to 2.  Filling in our upper and lower bounds we have \frac{1}{2}[( \frac{2(2^3)}{3}+3(2))-0] which simplifies to \frac{1}{2}( \frac{16}{3}+6) and \frac{1}{2}( \frac{16}{3}+ \frac{18}{3})= \frac{1}{2}( \frac{34}{3}) which is 17/3 or 5.667
7 0
3 years ago
Please help!!!! ASAP I’ll mark you as brainliest
KatRina [158]

Answer:

Vel_jet_r =  (464.645 mph)  North + (35.35 mph) East

||Vel_jet_r|| =  465.993 mph

Step-by-step explanation:

We need to decompose the velocity of the wind into a component that can be added  (or subtracted from the velocity of the jet)

The velocity of the jet

500 mph North

Velocity of the wind

50 mph SouthEast = 50 cos(45) East + 50 sin (45) South

South = - North

Vel_ wind = 50 cos(45) mph  East  -  50 sin (45) mph North

Vel _wind =  35.35 mph  East  -  35.35 mph North

This means that the resulting  velocity of the jet is equal to

Vel_jet_r =  (500 mph - 35.35 mph) North + 35.35 mph East

Vel_jet_r =  (464.645 mph)  North + (35.35 mph) East

An the jet has a magnitude velocity of

||Vel_jet_r|| =  sqrt ((464.645 mph)^2 + (35.35 mph)^2)

||Vel_jet_r|| =  465.993 mph

7 0
3 years ago
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