We are given 2 sides 18.7, 16.1 and a NON-included angle.
We have to calculate the altitude of the triangle.
altitude = 18.7 * sine (35)
altitude = 18.7 * 0.57358
altitude =
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10.725946
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In this case, side c is greater than the altitude and is less than side a so 2 two triangles will be formed.
Source:
http://www.1728.org/trigssa.htm
Answer:
The shadow is decreasing at the rate of 3.55 inch/min
Step-by-step explanation:
The height of the building = 60ft
The shadow of the building on the level ground is 25ft long
Ѳ is increasing at the rate of 0.24°/min
Using SOHCAHTOA,
Tan Ѳ = opposite/ adjacent
= height of the building / length of the shadow
Tan Ѳ = h/x
X= h/tan Ѳ
Recall that tan Ѳ = sin Ѳ/cos Ѳ
X= h/x (sin Ѳ/cos Ѳ)
Differentiate with respect to t
dx/dt = (-h/sin²Ѳ)dѲ/dt
When x= 25ft
tanѲ = h/x
= 60/25
Ѳ= tan^-1(60/25)
= 67.38°
dѲ/dt= 0.24°/min
Convert the height in ft to inches
1 ft = 12 inches
Therefore, 60ft = 60*12
= 720 inches
Convert degree/min to radian/min
1°= 0.0175radian
Therefore, 0.24° = 0.24 * 0.0175
= 0.0042 radian/min
Recall that
dx/dt = (-h/sin²Ѳ)dѲ/dt
= (-720/sin²(67.38))*0.0042
= (-720/0.8521)*0.0042
-3.55 inch/min
Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min
Answer:
The answer is C
Hope this helps!
Mark me brainliest if I'm right ;)
Answer:
h < 7
Step-by-step explanation:
-8 < -4h + 20
4h < 28 / : 4
h < 7
Answer:
mean if 7
Step-by-step explanation:
the mean is 7
