Answer:
A. 2
Step-by-step explanation:

Use any two points given in the table of values. Let's use (1, 5), (3, 9)
Let,


Plug these values into the slope formula:



Answer:
425.25
Step-by-step explanation:
Since we are given 36th term as 14 and we know common difference is
, it means that from the first term, we add
to each and get 14 on the 36th term. To figure out the first term, thus, we have to subtract
35 times from 14. Let's do it to get first term:

The sum of arithmetic sequence formula is:
![S_{n}=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Where,
is the sum of nth term (we want to figure this out for first 36 terms)
is the first term (we figured this out to be 9.625)
is the term number (36 for our case)
is the common difference (given as
)
Substituting all the values, we get:
![S_{36}=\frac{36}{2}[2(9.625)+(36-1)(\frac{1}{8})]\\S_{36}=18[19.25+4.375]\\S_{36}=18[23.625]\\S_{36}=425.25](https://tex.z-dn.net/?f=S_%7B36%7D%3D%5Cfrac%7B36%7D%7B2%7D%5B2%289.625%29%2B%2836-1%29%28%5Cfrac%7B1%7D%7B8%7D%29%5D%5C%5CS_%7B36%7D%3D18%5B19.25%2B4.375%5D%5C%5CS_%7B36%7D%3D18%5B23.625%5D%5C%5CS_%7B36%7D%3D425.25)
First answer choice is right.
Answer: very too bad for you buddy study nexts time
Step-by-step explanation:
Answer:
The initial value is $78
Step-by-step explanation:
Given

(weekly)
Required
Determine the initial value
The initial value is the amount he has in its bank account before making his weekly savings.
From the question, we have that his initial balance is $78.
Hence, the initial value is $78
However, his weekly balance can be expressed as:

Represent number of weeks with x; So, we have:


Answer:
For this case the confidence interval is given by :

Step-by-step explanation:
Data provided
represent the sample mean for the fuel efficiencies
population mean
s=2.51 represent the sample standard deviation
n=601 represent the sample size
Confidence interval
The formula for the confidence interval of the true mean is given by:
(1)
The degrees of freedom for this case is given by:
The Confidence level for this case is 0.95 or 95%, and the significance level
and
and the critical value is given by
Replcing into the formula for the confidence interval is given by:
For this case the confidence interval is given by :
