Ask question

Ask question

All categories

3 years ago

13

hellooooo guyssssddddddsss i was talking to some people help me find them if you are them tell me and tyyyyyyyyyyyyyyyyyyyyyyyyy

yyyyyyyyyyyy

2 answers:

mash [69]3 years ago

5 0

Huh

hmmm

Mmmmmmmmmmmmmm

ziro4ka [17]3 years ago

3 0

Answer: sure i'll help...who are they?

Explanation:

You might be interested in

Find the magnitude of the two pulling forces P and Q when their resultant is 50 N at 20° with Q. P 20°

morpeh [17]

Two forces P and Q whose resultant is 10Newton are at right angles to each other. If P makes 30 degrees with resultant.Show me the workings of the magnitude of Q in Newton and the diagram of the vectors.

7 0

3 years ago

2–25 Consider a medium in which the heat conduction equation is given in its simplest form as

barxatty [35]

Answer:

d) Is the thermal conductivity of the medium constant or variable.

Explanation:

As we know that

Heat equation with heat generation at unsteady state and with constant thermal conductivity given as

$\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}+\dfrac{d^2T}{dz^2}+\dfrac{\dot{q}_g}{K}=\dfrac{1}{\alpha }\dfrac{dT}{dt}$

With out heat generation

$\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}+\dfrac{d^2T}{dz^2}=\dfrac{1}{\alpha }\dfrac{dT}{dt}$

In 2 -D with out heat generation with constant thermal conductivity

$\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}=\dfrac{1}{\alpha }\dfrac{dT}{dt}$

Given equation

$\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}=\dfrac{1}{a }\dfrac{dT}{dt}$

So we can say that this is the case of with out heat generation ,unsteady state and with constant thermal conductivity.

So the option d is correct.

d) Is the thermal conductivity of the medium constant or variable.

3 0

3 years ago

For this assignment, you will write a program to determine the time and date corresponding to an elapsed number of seconds since

Karolina [17]

A Python program should be written to produce output that corresponds to the given hour, minute, second, day of the month, month's name, year, and day of the week's name.

present_year=2016

present_month="January"

present_date="1"

present_day="Friday"

present_hour=0

present_minute=0

present_second=0

input<-from user(seconds)//taking imput from the user using Python program

total_seconds=input

//checking with seconds

if(total_seconds<60)

present_second+=total_seconds

else

total_minutes=total_seconds/60

remaining_seconds=total_seconds-total_minutes*60

present_second+=remaining_seconds

//checking with minutes

if(total_minutes<60)

present_minute+=total_minutes

else

total_hours=total_minutes/60

remaining_minutes=total_minutes-total_hours*60

present_minute+=remaining_minutes

//checklng with hours

if(total_hours<24)

present_hour+=total_hours

else

total_days=total_hours/24

remaining_hours=total_hours-total_days*24

present_hour+=remaining_hours

//checking with days

total_weeks=total_days/7

remaining_day=total_days-total_weeks*7

switch(remaining_day)

case 1:

present_day="Friday"

case 2:

present_day="Saturday"

case 3:

present_day="Sundayday"

case 4:

present_day="Monday"

case 5:

present_day="Tuesday"

case 6:

present_day="Wedday"

case 7:

present_day="Thursday"

//checking with years

if(total_days>366)

while(total_days)

if(present_year%4==0)

total_days-=366

present_year+=1

if(present_year%4!=4)

total_days-=365

present_year+=1

if(present_year%4!=0&&total_days<365)

break;

if(present_year%4==0&&total_days<366)

break;

//checking with months and date

if(total_days<=366)

while(total_days)

if(present_month="January")

present_date++

total_days--

if(present_date==31)

present_month="February"

present_date=0

if(present_month="February")

present_date++

total_days--

if(present_date==28&&present_year%4!=0)

present_month="March"

present_date=0

if(present_date==29&&present_year%4==0)

present_month="March"

present_date=0

if(present_month="March")

present_date++

total_days--

if(present_date==31)

present_month="April"

present_date=0

if(present_month="April")

present_date++

total_days--

if(present_date==30)

present_month="May"

present_date=0

if(present_month="May")

present_date++

total_days--

if(present_date==31)

present_month="June"

present_date=0

if(present_month="June")

present_date++

total_days--

if(present_date==30)

present_month="July"

present_date=0

if(present_month="July")

present_date++

total_days--

if(present_date==31)

present_month="August"

present_date=0

if(present_month="August")

present_date++

total_days--

if(present_date==31)

present_month="September"

present_date=0

if(present_month="September")

present_date++

total_days--

if(present_date==30)

present_month="October"

present_date=0

if(present_month="October")

present_date++

total_days--

if(present_date==31)

present_month="November"

present_date=0

if(present_month="November")

present_date++

total_days--

if(present_date==30)

present_month="December"

present_date=0

if(present_month="December")

present_date++

total_days--

if(present_date==31)

present_month="January"

present_date=0

//printing present time

print present_hour:present_minute:present_second present_date present_month present_year present_day

Learn more about Python program here:

brainly.com/question/28691290

#SPJ4

3 0

2 years ago

Air is compressed adiabatically from p1 1 bar, T1 300 K to p2 15 bar, v2 0.1227 m3 /kg. The air is then cooled at constant volum

sashaice [31]

Answer:

Work done for the adiabatic process = -247873.6 J/kg = - 247.9 KJ/kg

Heat transfer for the constant volume process = - 244.91 KJ/kg

Explanation:

For the first State,

P₁ = 1 bar = 10⁵ Pa

T₁ = 300 K

V₁ = ?

Second state

P₂ = 15 bar = 15 × 10⁵ Pa

T₂ = ?

V₂ = 0.1227 m³/kg

Third state

P₃ = ?

T₃ = 300 K

V₃ = ?

We require the workdone for step 1-2 (which is adiabatic)

And heat transferred for steps 2-3 (which is isochoric/constant volume)

Work done for an adiabatic process is given by

W = K(V₂¹⁻ʸ - V₁¹⁻ʸ)/(1 - γ)

where γ = ratio of specific heats = 1.4 for air since air is mostly diatomic

K = PVʸ

Using state 2 to calculate for k

K = P₂V₂ʸ = (15 × 10⁵)(0.1227)¹•⁴ = 79519.5

We also need V₁

For an adiabatic process

P₁V₁ʸ = P₂V₂ʸ = K

P₁V₁ʸ = K

(10⁵) (V₁¹•⁴) = 79519.5

V₁ = 0.849 m³/kg

W = K(V₂¹⁻ʸ - V₁¹⁻ʸ)/(1 - γ)

W = 79519.5 [(0.1227)⁻⁰•⁴ - (0.849)⁻⁰•⁴]/(1 - 1.4)

W = (79519.5 × 1.247)/(-0.4) = - 247873.6 J/kg = - 247.9 KJ/kg

To calculate the heat transferred for the constant volume process

Heat transferred = Cᵥ (ΔT)

where Cᵥ = specific heat capacity at constant volume for air = 0.718 KJ/kgK

ΔT = T₃ - T₂

We need to calculate for T₂

Assuming air is an ideal gas,

PV = mRT

T = PV/mR

At state 2,

V/m = 0.1227 m³/kg

P₂ = 15 bar = 15 × 10⁵ Pa

R = gas constant for air = 287.1 J/kgK

T₂ = 15 × 10⁵ × 0.1227/287.1 = 641.1 K

Q = 0.718 (300 - 641.1) = - 244.91 KJ/kg

7 0

3 years ago

Use the following assumptions for problems 1 and 2:

Salsk061 [2.6K]

Answer:

The text file attached has the detailed solution of all the parts individually.

6 0

3 years ago