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3 years ago

Describe how the Rotary Engine works.

Engineering

1 answer:

LekaFEV [45]3 years ago

8 0

Answer:

Rotary engine was early known by the name of internal combustion engine. It convert heat from a high pressure of combustion. The main advantage of rotary engine is that it can be operate with less number of vibration. It works on the principle of converting pressure into rotating motion. In rotary engine the expansion pressure is applied on the flank rotor.

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Write a function call with arguments tensPlace, onesPlace, and userInt. Be sure to pass the first two arguments as pointers. Sam

Trava [24]

Answer:

#include <stdio.h>

void SplitIntoTensOnes(int* tensDigit, int* onesDigit, int DecVal){

*tensDigit = (DecVal / 10) % 10;

*onesDigit = DecVal % 10;

return;

}

int main(void) {

int tensPlace = 0;

int onesPlace = 0;

int userInt = 0;

userInt = 41;

SplitIntoTensOnes(&tensPlace, &onesPlace, userInt);

printf("tensPlace = %d, onesPlace = %d\n", tensPlace, onesPlace);

return 0;

}

4 0

3 years ago

When was Lamborghini's Made<br> A.) 2004<br> B.) 1963<br> C.) 1923<br> D.) 1990

Serjik [45]

Answer:

1963

Explanation:

Sant'Agata Bolognese is a small comune in the Metropolitan City of Bologna, Emilia-Romagna, in the north of Italy. It is notable for being the headquarters of the luxury automobile manufacturer Automobili Lamborghini. It is named after Saint Agatha of Sicily.

7 0

3 years ago

1. A company has an annual demand for a product of 2000 units, a carrying cost of $20per unit per year, and a setup cost of $100

Xelga [282]

Answer:

B the EOQ after setup reduction.

5 0

2 years ago

A rigid tank contains 10 kg of water at 90°C. If 8 kg of the water is in the liquid form and the rest is in the vapor form, dete

wlad13 [49]

Answer:

The pressure in the tank is 70.183 k Pa

The volume of the tank is 4.73 m³

Explanation:

Volume of the liquid phase

v(f) = m(f).v(f)

= 8 kg . 0.001036 m³/kg

= 0.008288 m³

Volume of the vapor phase

v(g) = m(g).v(g)

=2 kg . 2.3593 m³/kg

= 4.7186 m³

Volume of the tank = Volume of the liquid phase + Volume of the vapor phase

Volume of the tank

= 0.008288 m³ + 4.7186 m³ = 4.73 m³

5 0

3 years ago

Read 2 more answers

Chaplets are used to support a sand core inside a sand mold cavity. The design of the

ziro4ka [17]

Answer:

a) 2 chaplets

b) 9 chaplets

Explanation:

Before we can determine the minimum number of chaplets that should be placed beneath and above the core, we must know the mass of the sand used to make the surface of the mold cavity as well as the mass of the steel metal poured inside the mold.

Density is defined as the ratio of mass of a substance to its density.

Density = Mass/Volume

For the STEEL:

Density of steel = 7.82g/cm³

Volume = volume of the core = 5450cm³

Mass = Density × Volume

Mass of steel = 7.82×5450

Mass of steel = 42619g

Mass of steel in kg = 42.619kg

For the SAND:

Density of sand = 1.6g/cm³

Volume = volume of the core = 5450cm³

Mass = Density × Volume

Mass of sand = 1.6×5450

Mass of sand = 8720g

Mass of sand in kg = 8.72kg

a) Since the the chaplet support the sand from beneath the core, and each chaplet weighs 45N, we need to know the amount of force possessed by the sand.

Since the mass of the sand is 87.2kg

Weight = mass × acceleration due to gravity

Weight = 8.72×9.81

Weight of sand used to mold the core = 85.54N

Since 1 chaplet weighs 45N

This means that (85.54N/45N) i.e 1.9 which is approximately 2 chaplets must be placed beneath the core to sustain it before the steel metal is poured.

b) Since the metal poured in the core is steel, this means that the chaplet placed above the core must be able to withstand the strength of the steel.

Weight of steel = mass of steel × acceleration due to gravity

Weight of steel = 42.619×9.81

Weight of steel = 418.09N

Since one chaplet weigh 45N, the amount of chaplets that must be placed above the core is;

418.09/45

= 9.3

Therefore the minimum number of chaplets that should be placed above the core after pouring steel metal is 9chaplets.

4 0

3 years ago