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Gennadij [26K]
3 years ago
11

Technician A says that tire markings now include load ratings on tires. Technician B says that they are only included on truck t

ires. Who is correct?
A) Technician A
B) Technician B
C) Both
D) Neither
Engineering
1 answer:
Ludmilka [50]3 years ago
5 0
Technician A is correct hope this helps
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Which of these material properties determines how much heat you must supply to an object to raise it by a given temperature diff
Finger [1]

Answer:

specific heat

Explanation:

7 0
3 years ago
A circuit is a pathway for electron flow.
Fofino [41]

Answer:

True

False

Wire color

True

False

True

3 0
3 years ago
1. A first class lever in statistics equilibrium has a 75 Ib resistance force and a 20 Ib effort force. The lever's effort force
Mashutka [201]

Answer:

1. 3.75

2. 1.39 ft

Explanation:

The mechanical advantage is the ratio of the resistance force to the effort force.

MA = 75 lb / 20 lb

MA = 3.75

The sum of the torques about the fulcrum equals zero.

∑τ = Iα

(20 lb) (5.2 ft) − (75 lb) x = 0

x = 1.39 ft

Round as needed.

8 0
3 years ago
An intersection with a four phase signal has a displayed red time of 35 seconds, a start-up lost time of 2 seconds, a yellow tim
Temka [501]

Answer:

53 sec / cycle

Explanation:

Displayed red time = 35 seconds

Start up lost time = 2 seconds

Yellow time = 4 seconds

Red time = 1 second

Total lost time L = 2n + r

L = lost time

n = number of phase

R = red time

35+2+4+4*1

= 45

L = 2x4+45

= 53 sec/cycle

The total lost time is typically calculated as 53 seconds per cycle

3 0
3 years ago
An automobile having a mass of 884 kg initially moves along a level highway at 68 km/h relative to the highway. It then climbs a
IRISSAK [1]

Answer:

ΔK.E. = - 142.72 kJ

Explanation:

mass = 884 kg

initial velocity = 68 km/h = 68 \times \frac {5}{18} = 18.89 m/s

final velocity = 0 m/s

height = 69 m

change in kinetic energy :

ΔK.E. = \dfrac{1}{2}m(v_f^2-v_i^2)

ΔK.E. =\dfrac{1}{2}\times 884 \times (0^2-18.89^2)

ΔK.E. =-142,716.05 J

ΔK.E. =-142.72 kJ

hence change in  kinetic energy of the automobile is  -142.72 kJ

6 0
4 years ago
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