2 years ago

Please help I would be very grateful

Mathematics

1 answer:

Fittoniya [83]2 years ago

6 0

Let’s see um so first you..

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The ratio of blue cars to red cars in a garage is 9:7. If there are 49 red cars in the garage then how many blue cars must be in

m_a_m_a [10]

Answer:

Blue cars, B = 63 cars

Step-by-step explanation:

Let the blue cars be B.

Let the red cars be R.

Given the following data;

Ratio of B:R = 9:7 = 9 + 7 = 16

Red cars, R = 49

To find the number of blue cars;

First of all, we would determine the total number of cars using the expression;

R = 7/16 * x = 49

7x = 49 * 16

7x = 784

x = 112 cars

Now, we can find the number of blue cars;

B = 9/16 * 112

B = 1008/16

Blue cars, B = 63 cars

3 0

3 years ago

7.6x = 64 is approximately 3.05. is this the solution?

lisov135 [29]

7.6x = 64
x = 64/7.6
x = 8.4210526316 
So, 3.05 is NOT the solution

3 0

3 years ago

X y

Strike441 [17]

Answer:

Step-by-step explanation:

3-1=2

2-1=1

1-1=0

From this we can see that the constant rate of change is 1.

Hope it helps <3

6 0

3 years ago

Someone who knows the remainder theorem help!

Damm [24]

Answer:

○ D. Yes, x = 12 is a zero of the polynomial.

The quotient is x + 22, and the remainder is 0.

Step-by-step explanation:

On a second thought, I knew something similar to that theorem because factoring them would determine if it has a remainder:

[x - 12][x + 22]

I am joyous to assist you anytime.

* I apologize for the previous answer I gave you.

5 0

4 years ago

A new car was valued at $28,000, and it's value depreciated to $14,000 over the next 3 years. Use the exponential equation for d

kompoz [17]

The exponential equation (in thousands) is:
$V = 28 e^{-rt}$
plug in t=3 yrs, and solve for 'r'.
$14 = 28 e^{-3r} \\ \\ \frac{1}{2} = e^{-3r} \\ \\ ln(\frac{1}{2}) = -3r \\ \\ r = \frac{ln(\frac{1}{2})}{-3} = 0.231 = 23.1%$

Find value of car when t = 10
$V = 28e^{-2.31} = 2.779$

8 0

3 years ago