All categories

3 years ago

Can y'all help me this question ASAP this all I need

Mathematics

1 answer:

Sergio [31]3 years ago

6 0

5/8x + 1/5x can be written with a common denominator:
25/40x+ 8/40x = 99

This can be simplified to:
33/40x = 99

Next times both sides by 40
33x = 3960

Then, divide both sides by 33
x = 3960/33
x = 120

You might be interested in

NO LINKS!!! Find the arc measure and arc length of AB. Then find the area of the sector ABQ.

Norma-Jean [14]

Answer:

<u>Arc Measure</u>: equal to the measure of its corresponding central angle.

<u>Formulas</u>

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right)$

$\textsf{Area of a sector of a circle}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$

$\textsf{(where r is the radius and the angle }\theta \textsf{ is measured in degrees)}$

<h3><u>Question 39</u></h3>

Given:

r = 7 in
$\theta$ = 90°

Substitute the given values into the formulas:

Arc AB = 90°

$\textsf{Arc length of AB}=2 \pi (7) \left(\dfrac{90^{\circ}}{360^{\circ}}\right)=3.5 \pi=11.00\:\sf in\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{90^{\circ}}{360^{\circ}}\right) \pi (7)^2=\dfrac{49}{4} \pi=38.48\:\sf in^2\:(2\:d.p.)$

<h3><u>Question 40</u></h3>

Given:

r = 6 ft
$\theta$ = 120°

Substitute the given values into the formulas:

Arc AB = 120°

$\textsf{Arc length of AB}=2 \pi (6) \left(\dfrac{120^{\circ}}{360^{\circ}}\right)=4\pi=12.57\:\sf ft\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{120^{\circ}}{360^{\circ}}\right) \pi (6)^2=12 \pi=37.70\:\sf ft^2\:(2\:d.p.)$

<h3><u>Question 41</u></h3>

Given:

r = 12 cm
$\theta$ = 45°

Substitute the given values into the formulas:

Arc AB = 45°

$\textsf{Arc length of AB}=2 \pi (12) \left(\dfrac{45^{\circ}}{360^{\circ}}\right)=3 \pi=9.42\:\sf cm\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (12)^2=18 \pi=56.55\:\sf cm^2\:(2\:d.p.)$

8 0

2 years ago

I want help its urgent!!! <br><br>(iv), (v), (vi) Questions

Artist 52 [7]

Solution:

iv) Given equation: $x^{2} - y^{2} - 4x - 2y + 3$

Since we are given two variables, we need to split the original expression into two quadratic expressions as

$x^{2} - 4x + 4 - y^{2} - 2y - 1$

Factoring x first:

$x^{2} - 4x + 4 =$ $x^{2} - 2x - 2x + 4$

= $x (x - 2) - 2 (x-2)$

= $(x-2)(x-2)$

$= (x-2)^{2}$

Factoring y now:

$-y^{2} - 2y - 1 = -1(y^{2} + 2y + 1)$

= $-1(y^{2} + y + y + 1)$

= $-1[ y(y+1) + 1(y+1)]$

= $-1 [(y+1)(y+1)]$

= $(y+1)(-y-1)$

Therefore, the original expression becomes

$(x-2)^{2}+(y+1)(-y-1)\\or \\(x-2)(x-2) + (y+1)(-y-1)$

7 0

3 years ago

I need help with this 1 question

Gemiola [76]

7 × 8 × 8 = 448

and that's it

6 0

3 years ago

Read 2 more answers

5+ 2a/-3= 5/11<br> solve for A please

xxTIMURxx [149]

Let's solve it step-by-step.

5+ 2a/-3= 5/11

Step 1: Simplify both sides of the equation.

5+ 2a/-3= 5/11

-2/3a+5=5/11

Step 2: Subtract 5 from both sides.

-2/3a+5-5=5/11-5

-2/3a=-50/11

Step 3: Multiply both sides by 3/(-2).

a=75/11

So, the answer is a=75/11.

7 0

3 years ago

Write and solve an addition or subtraction equation to find the missing angle measure

nlexa [21]

Answer:

n = 60°

Step-by-step explanation:

60° + n + 60° = 180° ( straight line angles)

-> n + 120° = 180°

-> n = 180° - 120°

-> n = 60°

4 0

2 years ago