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Virty [35]
3 years ago
5

Use a calculator to find each sum or difference. Round your answer to the nearest hundredth.

Mathematics
1 answer:
motikmotik3 years ago
8 0

Answer:

54.87

69.08

Step-by-step explanation:

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5(2+4(3)+-5+-2(7)Evaluate the expression
Andru [333]

Answer:

-25

Step-by-step explanation:

7 0
3 years ago
Tarana mailed 20 greetings cards. 9 of them were mailed to USA. What percentage of the cards were mailed to USA?
Elza [17]

Answer:

45%

Step-by-step explanation:

9/20=0.45 (Divide it first), 45/100=45% (45/100 because 100 makes 1 whole -all 20 cards-)

7 0
3 years ago
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
Tell which number is greater.<br><br> 1/3, 30%
Olin [163]
Mhm pretty sure 1/3
8 0
3 years ago
Need help urgently, please
Kaylis [27]
Answer: 26

There’s nothing here for me to solve
3 0
3 years ago
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