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3 years ago

At what temperature will a sample of neon gas exert a pressure of 0.750 atm and exhibit a density of 1.45 gL

Chemistry

1 answer:

Maslowich3 years ago

3 0

Answer:

127K

Explanation:

Recall that the density of a gas (ρ) is related to the molar mass of the gas (M), the ideal gas constant (R), and the temperature in Kelvin (T). This relationship is described by the equation below.

ρ=PMRT

We are asked to solve for the temperature at which neon gas, Ne(g), will have a density of ρ=1.45gL. Rearrange the equation above to solve for T and substitute the given values into the equation.

ρT=PMRT=PMRρ=(0.750atm)(20.180gmol)(0.08206L atmmol K)(1.45gL)=127.2K

Therefore, after rounding to three significant figures, we find that the temperature is approximately 127K.

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Assume that adhesin gene of Neisseria gonorrhoeae, the pathogen that causes gonorrhea, were mutated. What is the most likely eff

guajiro [1.7K]

When the adhesin gene of Neisseria gonorrhoeae were mutated, the pathogen will be unable to attach to the host cells.

<h3>What do you mean by Pathogens?</h3>

Pathogens may be defined as disease-causing agents. These are mostly microorganisms that infect the body of animals as well as humans.

Adhesin gene plays a very vital role in the attachment of pathogens to the host cells. It is the site where pathogen attack and attaches to host cells and then enters the body to play their function i.e. replication, a decline in the host immune system, and finally disease caused.

Therefore, when the adhesin gene of Neisseria gonorrhoeae were mutated, the pathogen will be unable to attach to the host cells.

To learn more about Pathogens, refer to the link:

brainly.com/question/1008643

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5 0

3 years ago

Evidence that the Big Bang Theory actually occurred

VMariaS [17]

Answer:

Two major scientific discoveries provide strong support for the Big Bang theory: • Hubble's discovery in the 1920s of a relationship between a galaxy's distance from Earth and its speed; and • the discovery in the 1960s of cosmic microwave background radiation.

Explanation:

8 0

3 years ago

How does the concept of polarity relate to bond formation and molecular shape?

Ket [755]

Answer: heyyyooo

The bond polarity for each bond in a BH3 molecule is polar, due to the difference in electronegativities of the B and H atom. The molecular shape is trigonal planar, and the molecule is non-polar - because due to the symmetry of the molecule, the polarities cancel out.

Explanation:

hope this helps!

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3 years ago

An electrochemical cell contains a standard hydrogen electrode and a cathode consisting of a metallic chromium electrode, Cr(s),

stira [4]

Answer:

c. I, II and III

Explanation:

The cell is as follows

Cr / Cr⁺²(1M) // H⁺ ( 1 M ) / H₂

Standard reduction potential of hydrogen cell is zero . Standard reduction potential is negative E for Cr⁺² / Cr(1M) half cell

Cell potential = Ecathode - Eanode

= 0 - ( - E)

= E

E is cell potential and also standard cell potential or emf of the cell .

Standard reduction potential that is for Cr3+/Cr. is - E .

Hence statement I , II , III are right . IV th statement is wrong because of sign

Option c is correct.

5 0

3 years ago

Sulfur undergoes combustion to yield sulfur trioxide by the following reaction equation:

12345 [234]

Answer:

Therefore, the amount of heat produced by the reaction of 42.8 g S = (-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J

Explanation:

Given reaction: 2S + 3O₂ → 2 SO₃

Given: The enthalpy of reaction: ΔH = - 792 kJ

Given mass of S: w₂ = 42.8 g, Molar mass of S: m = 32 g/mol

In the given reaction, the number of moles of S reacting: n = 2

As, Number of moles: $n = \frac{mass\: (w_{1})}{molar\: mass\: (m)}$

∴ mass of S in 2 moles of S: $w_{1} = n \times m = 2\: mol \times 32\: g/mol = 64\: g$

Given reaction: 2S + 3O₂ → 2 SO₃

In this reaction, the limiting reagent is S

⇒ 2 moles S produces (- 792 kJ) heat.

or, 64 g of S produces (- 792 kJ) heat.

∴ 42.8 g of S produces (x) amount of heat

⇒ The amount of heat produced by 42.8 g S:

$x = \frac{(- 792\: kJ) \times 42.8\: g}{64\: g} = (-529.65)\: kJ$

$\Rightarrow x = (-5.2965 \times 10^{2})\: kJ = (-5.2965 \times 10^{5})\: J$

$(\because 1 kJ = 10^{3} J)$

Therefore, the amount of heat produced by the reaction of 42.8 g S = (-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J

8 0

4 years ago