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spayn [35]
3 years ago
10

The Doppler effect related change in wave frequency to what?

Chemistry
1 answer:
Irina18 [472]3 years ago
8 0

Answer:

Relative motion of source and observer.

Explanation:

Doppler Effect : It is the change in the observed frequency of the wave due to<em><u> relative motion of the source and object </u></em>.

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A sample of argon gas is at a pressure of 1.725x10^4 kPa and a temperature of 24°C in a rigid 20 L tank. How many moles of argon
Paraphin [41]
To find how many moles of the gas you can use ideal gas formula. Remember to change the temperature unit to Kelvin. Since the pressure using kpa, the constant used would be 8.314 kpa*L  / mol*K
PV=nRT
n= PV/RT
n= 17,250 kpa * 20  /   8.314 * (24+273.15)K
n=139.64moles
4 0
4 years ago
What can an experiment to use to distinguish between a strong acid and a strong base
aivan3 [116]

The pH meter can only be used to differentiate between weak and strong acids providing that the concentrations are known. However, it is convenient to determine the concentration of an acid (or base) by titration.

4 0
4 years ago
A 100 gram block is placed on a scale that is known to have a 12% error. What will the scale read?
sesenic [268]

The scale will read <u>112 grams.</u>

Why?

Since we already know the percent error of the scale (12%) and we also know the mass of the block that is placed on the scale, we can calculate what will be the read of the scale by using the following formula:

ScaleRead=100g+(100g*\frac{12}{100})=100g+(100g*0.12)=100g+12g\\\\ScaleRead=112g

We can see that the scale will read 112 grams.

Let's verify that we are right by using the following formula to verify if the obtained value for the scale read will be 12%:

PercentError=\frac{ActualValue-RealValue}{RealValue}*100=\frac{112g-100g}{100g}*100\\\\PercentError=\frac{12g}{100g}*100=0.12*100=12(percent)

Hence, we can see that the scale will read <u>112 grams.</u>

Have a nice day!

7 0
4 years ago
Hurry!!!!!!!!!!!!!!! Match the terms to the correct descriptions.
viva [34]

The type of energies or the words in this item are matched with the given descriptions. The lists below are as follow.<span>

<span>a. The word that best match this description is MECHANICAL energy. In most sources, mechanical energy is described to be that energy that is possessed by an object with respect to its motion and position. </span>

<span>b. The answer to this item is LIGHT energy. This type of energy can be created through different means (i.e. radiation, chemical, and mechanical). This is the energy emitted by hot objects such as the sun, lasers, and bulbs.</span>

<span>c. The type of energy that is transferred by the movement of the electrons through a conductor is ELECTRICAL energy. The movement of the electrons along the line is commonly called as the current. Moreover, this is also a type of kinetic energy because of the movement of the electrons. Thus, the faster the movement of the electron the higher is the energy. </span>

<span>d. The type of energy that is stored in batteries or food is CHEMICAL energy. This type of energy is that which is stored in the bonds of the different chemical compounds. This is also most commonly released when reaction between elements/compounds happen.</span>

<span>e. The energy that travels through vibrations and waves is SOUND energy. As given above, this is associated with the movement or vibrations of the matter. This is also a type of mechanical energy because of the waves produced through to the vibrations.</span>

<span>f. The type of energy that is found in the nucleus and atoms is the NUCLEAR energy.  Nuclear reactions most often released this type of energy simultaneous with the generation of heat. </span>

<span>g. The stored energy is called the POTENTIAL energy. The equation for this energy is mgh where h is the height, pertaining to the position of the object. Once the object is released, it will be converted to other forms of energy. </span>

<span>h. The answer to this item is THERMAL energy. This type of energy can be transferred in three different ways: (1) conduction, (2) convection, and (3) radiation.</span></span>

3 0
4 years ago
Read 2 more answers
How much work must be done on a 5-kg snowboard to increase its speed from 2 m/s to 4 m/s?
Alekssandra [29.7K]

Answer:

Option C = 30 j

Explanation:

Given data:

mass of snowboard = 5 Kg

Initial speed = 2 m/s

final speed = 4 m/s

work done = ΔE= ?

ΔE= change in kinetic energy

Solution:

Formula:

K.E (initial) = 1/2 × mv²

K.E (initial)  = 1/2 × 5 Kg . (2m/s)²

K.E (initial) = 1/2 × 20 Kg.m²/s²

K.E (initial) = 10 Kg.m²/s² or 10 J      

   Kg.m²/s² = J

K.E (finial) = 1/2 × mv²

K.E (finial) = 1/2 ×  5 Kg . (4m/s)²

K.E (finial) = 1/2 ×  5 Kg . 16 m²/s²

K.E (finial) = 1/2 × 80 Kg.m²/s²

K.E (finial) = 40 Kg.m²/s²  or 40 J

work done =  ΔE = K.E (finial) - K.E (initial)

work done =  ΔE = 40 J - 10 J

work done =  ΔE = 30 J

6 0
3 years ago
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