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3 years ago

8

What is this balanced? Al2O3---> Al+O2

1 answer:

saveliy_v [14]3 years ago

6 0

The balanced equation :

<em>2Al₂O₃⇒ 4Al+3O₂</em>

<h3>Further explanation</h3>

Given

Reaction

Al₂O₃⇒ Al+O₂

Required

Balanced equation

Solution

A chemical reaction is said to be balanced if the number of elements involved in the reaction is the same (either the reactants or the products)

The reaction above is said to be unbalanced because the number of elements Al and O in the reactants and products is not the same.

The balancing step

1. Give a coefficient

Al₂O₃⇒ aAl+bO₂

2. Make an equation

Al, left = 2, right = a⇒a=2

O, left = 3, right = 2b⇒2b=3⇒b=3/2

The equation becomes :

Al₂O₃⇒ 2Al+3/2O₂ x2

<em>2Al₂O₃⇒ 4Al+3O₂</em>

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Calculate the wavelength for the transition from n = 4 to n = 2, and state the name given to the spectroscopic series to which t

finlep [7]

Answer:

The wavelength for the transition from n = 4 to n = 2 is<u> 486nm</u> and the name name given to the spectroscopic series belongs to <u>The Balmer series.</u>

Explanation

lets calculate -

Rydberg equation- $\frac{1}{\pi } =R(\frac{1}{n_1^2} -\frac{1}{n_2^2})$

where , $\pi$ is wavelength , R is Rydberg constant ( $1.097\times10^7$ ), $n_1$ and $n_2$ are the quantum numbers of the energy levels. (where $n_1=2 , n_2=4$ )

Now putting the given values in the equation,

$\frac{1}{\pi }=1.097\times10^7\times(\frac{1}{2^2} -\frac{1}{4^2} )$ $=2056875m^-^1$

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= $4.86\times10^-^7$ = 486nm

<u> Therefore , the wavelength is 486nm and it belongs to The Balmer series.</u>

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